Answer: 1, 5, 2
All you do is subtract 3 from the y
The answer is 6/40. All the others equal 1/5.
The value of constant c for which the function k(x) is continuous is zero.
<h3>What is the limit of a function?</h3>
The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.
To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:


Provided that:

Using l'Hospital's rule:

Therefore:

Hence; c = 0
Learn more about the limit of a function x here:
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The fraction he added is 6/30, or 1/5.
I'm not 100% sure about the equation you want me to use but I did the work this way:
5/6+x/30=31/30 (the denominator has to equal 30 because you are adding. You need a common denominator which is why you need to change 5/6. We can label the numerator as a hidden value x)
25/30+x=31/30
You can then work backwards and basically subtract 25 from 31 and get 6; so x=6