5%, 0.5, 5 from smallest to largest.
Answer:
All of the positive integers that can divide evenly into 35 (they are the factors) are:
1, 5, 7, 35
All others, like 2, 3, 13, ... create a remainder that is not 0.
Now, you may (or soon will be) learning about the prime factors of 35 (not 1, and only divisible by itself and 1). They are:
5, 7
Step-by-step explanation:
Answer:
14^3 = 2,744. Common factors are 1,2,4,7,8,14,28,49,56...
13^4 = 2,197. Common factors are 1, 13, 169, and 2197.
<span>Simplifying
(6a + -8b)(6a + 8b) = 0
Multiply (6a + -8b) * (6a + 8b)
(6a * (6a + 8b) + -8b * (6a + 8b)) = 0
((6a * 6a + 8b * 6a) + -8b * (6a + 8b)) = 0
Reorder the terms:
((48ab + 36a2) + -8b * (6a + 8b)) = 0
((48ab + 36a2) + -8b * (6a + 8b)) = 0
(48ab + 36a2 + (6a * -8b + 8b * -8b)) = 0
(48ab + 36a2 + (-48ab + -64b2)) = 0
Reorder the terms:
(48ab + -48ab + 36a2 + -64b2) = 0
Combine like terms: 48ab + -48ab = 0
(0 + 36a2 + -64b2) = 0
(36a2 + -64b2) = 0
Solving
36a2 + -64b2 = 0
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '64b2' to each side of the equation.
36a2 + -64b2 + 64b2 = 0 + 64b2
Combine like terms: -64b2 + 64b2 = 0
36a2 + 0 = 0 + 64b2
36a2 = 0 + 64b2
Remove the zero:
36a2 = 64b2
Divide each side by '36'.
a2 = 1.777777778b2
Simplifying
a2 = 1.777777778b2
Take the square root of each side:
a = {-1.333333333b, 1.333333333b}</span>
You can use the C. HL Theorem to prove the triangles congruent.
To use the HL THeorem to prove the triangles congruent, you have to check for three conditions.
1) The triangles are both right triangles.
2) Their hypotenuses are congruent
3) They have one pair of congruent legs.
The squares at the angle of the triangle indicate the triangles are right triangles. Since the triangles in the picture share one side, the hypotenuse, the hypotenuses of the triangles are congruent. The triangles also have one pair of congruent legs. Since all three conditions of the HL Theorem are met, the triangles are congruent.