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mr Goodwill [35]
2 years ago
15

9x-y= 29 and 9x + y = -29

Mathematics
2 answers:
ahrayia [7]2 years ago
6 0

Answer:

(0,-29) x = 0, y = -29

Step-by-step explanation:

Hatshy [7]2 years ago
4 0

Answer:

x= - 29 over 9 - 1 over 9y, y

Step-by-step explanation:

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$36.60 with the discount of 20%?
kenny6666 [7]

Answer: $29.28

Step-by-step explanation:

Question: $36.60 with the discount of 20%?

Steps:

Discount = Original Price * Discount %100

Discount = 36.6 × \frac{20}{100}

Discount = 36.6 × 0.2

You save = $$7.32

Final Price = Original Price - Discount

Final Price = 36.6 - 7.32

Final Price = $29.28

~I hope I helped :)~

4 0
3 years ago
Read 2 more answers
What is the area of this quadrilateral?<br> 3 ft<br> 4 ft<br> 3 fty
ipn [44]

Answer:

D

Step-by-step explanation:

12 square feet

7 0
2 years ago
Finding area of a sector
katen-ka-za [31]
The smaller sector is 360-255=105 degree
it is 105/360 portion of the whole circle, and the area of the whole circle is πr², r is 14
so the area of the smaller sector is (105/360)*π*14²
run those numbers through your calculator, use 3.14 for π, you get 179.5

if you are looking for area of the larger sector, it would be
(255/360)*π*14²=435.94
3 0
3 years ago
Find the constant rate of change for each linear function and interpret its meaning
Marina CMI [18]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

and to get it, we simply need two points off of the straight line, hmm let's use the ones in the picture below.

(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

3 0
2 years ago
10)
serious [3.7K]

Answer:

i think its B

Step-by-step explanation:

3 0
3 years ago
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