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mr Goodwill [35]
2 years ago
15

9x-y= 29 and 9x + y = -29

Mathematics
2 answers:
ahrayia [7]2 years ago
6 0

Answer:

(0,-29) x = 0, y = -29

Step-by-step explanation:

Hatshy [7]2 years ago
4 0

Answer:

x= - 29 over 9 - 1 over 9y, y

Step-by-step explanation:

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Answer the geometry question in the pic and save my life...
Anastasy [175]

Answer:

The answer should be A'(-9,3) B'(12,-6)

Step-by-step explanation:

If you dialate, you multiply every coordinate by 3. -3 x 3= -9. 1 x 3=3. 4 x 3= 12. -2 x 3= -6. So,  the last option is correct.

3 0
3 years ago
During the first year Sherry worked as a lifeguard, she was paid at a rate of $12.75 per hour.
lara [203]

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a

Step-by-step explanation:

5 0
3 years ago
what is the sum of the first 25 terms of an arithematic sequence if the sum of its 8th and 18th terms is 72?​
max2010maxim [7]

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Step-by-step explanation:

7 0
3 years ago
Quiz 1-2: Distance & Midpoint; Partitioning a Segment
nadya68 [22]

The distances between the given pairs of points are:

  • (-8, -2) and (6, -1);  d = 14.04
  • (-4, 5) and (4,0); d = 9.85
<h3>How to find the distance between two points?</h3>

The distance between two points (x₁, y₁) and (x₂, y₂) is given by:

d = √( (x₁ - x₂)^2 - (y₁ - y₂)^2)

1) The first pair of points is (-8, -2) and (6, -1), using the above formula we can see that the distance is:

d = √( (-8 - 6)^2 - (-2 +1)^2) = 14.04

2) The second pair is (-4, 5) and (4,0), and using the distance formula, we get:

d = √( (-4 - 5)^2 - (4 - 0)^2) = 9.85

If you want to learn more about the distance between points:

brainly.com/question/7243416

#SPJ1

3 0
1 year ago
2.Solve the following quadratic equations<br> i. 9x^2 - 1/16<br> ii. 2h^2 - 3h - 27
Juli2301 [7.4K]
i)~9x^2-\dfrac{1}{16}=0\iff9x^2=\dfrac{1}{16}\iff x^2=\dfrac{1}{9\cdot16}\iff \\\\x^2=\dfrac{1}{144}\iff x=\pm\sqrt{\dfrac{1}{144}}=\pm\dfrac{1}{12}\Longrightarrow\boxed{x=\pm\dfrac{1}{12}}


ii)~2h^2-3h-27=0\\\\\Delta=b^2-4ac\to \Delta=(-3)^2-4\cdot2\cdot(-27)\to\Delta=9+216=225\\\\&#10;\Longrightarrow h=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-(-3)\pm\sqrt{225}}{2\cdot2}=\dfrac{3\pm15}{4}\\\\\begin{cases}h_1=\dfrac{3+15}{4}=\dfrac{18}{4}\iff \boxed{h_1=\dfrac{9}{2}}\\h_2=\dfrac{3-15}{4}=\dfrac{-12}{4}\iff\boxed{h_2=-3}\end{cases}

4 0
3 years ago
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