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JulijaS [17]
2 years ago
5

How do I solve this?

Mathematics
1 answer:
snow_lady [41]2 years ago
5 0

Answer:

below the ans

Step-by-step explanation:

cos k = 5/23

= .21

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How do you do question b?
notsponge [240]

Part (b)

We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

\arcsin(4y) = x^2 + C\\\\\arcsin(4*0) = (0)^2 + C\\\\\arcsin(0) = C\\\\0 = C\\\\C = 0\\\\

-----------------

This means,

\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\

is the solution with the initial condition y(0) = 0.

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The anwser to your question is 1 and 5/7
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lesya692 [45]

Answer:

the third one is the correct answer

Step-by-step explanation:

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