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3 years ago

5

If 50% of a number is 170 and 20% of the same number is 68, find 70% of that number.

2 answers:

dlinn [17]3 years ago

3 0

Answer:

238

Step-by-step explanation:

MaRussiya [10]3 years ago

3 0

The answer to this is 119

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You solve an equation by finding the value that is?

Alex787 [66]

Yes I think that is what you do but others can elaborate more im sure

6 0

3 years ago

Brandon earns $6 for every shirt he sells. Which equation could Brandon use to determine the amount of money he earns (E) for an

7nadin3 [17]

E = 6s <=== ur equation

3 0

4 years ago

Read 2 more answers

The equations that must be solved for maximum or minimum values of a differentiable function w=f(x,y,z) subject to two constrai

sammy [17]

The Lagrangian is

$L(x,y,z,\lambda,\mu)=x^2+y^2+z^2+\lambda(4x^2+4y^2-z^2)+\mu(2x+4z-2)$

with partial derivatives (set equal to 0)

$L_x=2x+8\lambda x+2\mu=0\implies x(1+4\lambda)+\mu=0$

$L_y=2y+8\lambda y=0\implies y(1+4\lambda)=0$

$L_z=2z-2\lambda z+4\mu=0\implies z(1-\lambda)+2\mu=0$

$L_\lambda=4x^2+4y^2-z^2=0$

$L_\mu=2x+4z-2=0\implies x+2z=1$

Case 1: If $y=0$ , then

$4x^2-z^2=0\implies4x^2=z^2\implies2|x|=|z|$

Then

$x+2z=1\implies x=1-2z\implies2|1-2z|=|z|\implies z=\dfrac25\text{ or }z=\dfrac23$

$\implies x=\dfrac15\text{ or }x=-\dfrac13$

So we have two critical points, $\left(\dfrac15,0,\dfrac25\right)$ and $\left(-\dfrac13,0,\dfrac23\right)$

Case 2: If $\lambda=-\dfrac14$ , then in the first equation we get

$x(1+4\lambda)+\mu=\mu=0$

and from the third equation,

$z(1-\lambda)+2\mu=\dfrac54z=0\implies z=0$

Then

$x+2z=1\implies x=1$

$4x^2+4y^2-z^2=0\implies1+y^2=0$

but there are no real solutions for $y$ , so this case yields no additional critical points.

So at the two critical points we've found, we get extreme values of

$f\left(\dfrac15,0,\dfrac25\right)=\dfrac15$ (min)

and

$f\left(-\dfrac13,0,\dfrac23\right)=\dfrac59$ (max)

5 0

3 years ago

Michael has $317.89 in his bank account. He uses the money in his account to purchase new clothes for $48.73, lunch for $10.13 a

navik [9.2K]

Answer:

$226.57

Step-by-step explanation:

1. Subtract $48.73 from $317.89

2. Now you have $269.16 so subtract $10.13 from it

3. You should have $259.03 so subtract $32.46 from it

4. Finally you should get $226.57

4 0

3 years ago

A Kite of Area 255 m2 has one diagonal of length 9m . find the length of the other diagonal

Bas_tet [7]

$\\ \rm\longmapsto Area=255m^2$

$\\ \rm\longmapsto LB=255$

$\\ \rm\longmapsto 9L=255$

$\\ \rm\longmapsto L=\dfrac{255}{9}$

$\\ \rm\longmapsto L=28.3m$

6 0

3 years ago