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DedPeter [7]
3 years ago
10

You solve an equation by finding the value that is?

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
Yes I think that is what you do but others can elaborate more im sure
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HELP me ASAP i need help
irinina [24]

Answer:

sin 39 = BS / 500

0.629320391 * 500 = BS

BS = 314.6601955 feet

ie. h = 314.66 feet

3 0
4 years ago
A spinner Is divided into eight equal parts numbered 1 to 8. If the spinner is spun once, what is the probability that it stops
vampirchik [111]

Answer: C

Step-by-step explanation: they said they divided into uqual which 1/8= 1/4 Divide 1/4=.25

4 0
4 years ago
Consider the initial value problem 25y′′+40y′+16y=0, y(0)=a, y′(0)=−1. Find the critical value of a that separates solutions tha
Anna007 [38]

Answer:

Step-by-step explanation:

Given the differential equation

25y′′+40y′+16y=0

Using D operator to find the complementary solution

Since the Differential equation is equal to 0, then it doesn't have a partial solution.

25y′′+40y′+16y=0

25D² + 40D +16 = 0

25D² + 20D + 20D +16 = 0

5D(5D+4)+4(5D+4)= 0

(5D+4)=0 twice

D = -4/5 twice,

So the solution is a real and equal roots

y(t) = (A+B•t) exp(—0.8t)

Where A and B are constant

The initial value are.

y(0)=a, y′(0)=−1

y(0) = a = (A+B(0)) exp(—0.8(0))

a = A

Then, the constant A = a.

Now, y'(t)

y'(t)=B•exp(-0.8t)-0.8(A+B•t)exp(-0.8t

-1 = B - 0.8A

Since A =a

Then, B = 0.8a —1

The solution becomes

y(t) = (a+(0.8a-1)•t) exp(—0.8t)

For t>0

For positive,

a + (0.8a -1)> 0

1.8a > 1

a > 1/1.8

a > 10/18 > 5/9

a > 5/9.

6 0
4 years ago
I will do anything if you answer!!! There's a photo!!! PLEASE!!!
nekit [7.7K]
What do you mean picture?
7 0
3 years ago
Find the measure of line segment TU. Assume that lines which appear to be tangent to the circle are tangent.
Sedaia [141]

Given:

A figure of a circle. A secant SU and a tangent SR is drawn to the circle from the external point S.

To find:

The measure of the line segment TU.

Solution:

According to the secant tangent segment theorem, the square of tangent is equal to the product of secant and external segment of the secant.

Using secant tangent segment theorem, we get

SR^2=SU\times ST

(40)^2=(32+2x-2)\times (32)

1600=(30+2x)(32)

1600=960+64x

Subtract both sides by 960.

1600-960=64x

640=64x

Divide both sides by 64.

\dfrac{640}{64}=x

10=x

Now, the measure of the line segment TU is:

TU=2x-2

TU=2(10)-2

TU=20-2

TU=18

Therefore, the correct option is C.

6 0
3 years ago
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