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Papessa [141]
3 years ago
11

Which equation has the same solution as x^2-x+11=8

Mathematics
1 answer:
seraphim [82]3 years ago
3 0

Answer:

There are no real solutions to this equation.

Hope This Helps!

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3 pounds of gummie bears cost $8.97. <br> What will one pound cost?
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Answer:

2.99

Step-by-step explanation:

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Which of the expressions below could be factored quickly using the "difference of squares"? Select all that apply.
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Difference of squares method is a method that is used to evaluate the difference between two perfect squares.

For example, given an algebraic expression in the form:

can be factored as follows:

From the given expressions, the only expression containing two perfect squares with the minus sign in the middle is the expression in option A.

i.e.  

which can be factored as follows:

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Read 2 more answers
A car dealership pays $8,350 for a car. They mark up the price by 17.4% to get the retail price. What is the retail price of the
tangare [24]
$ 9802.9and it said the answer had to be 20 characters long so i wrote this
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3 years ago
See attachment below
KatRina [158]

Answer: Third Option

x=1.469743

Step-by-step explanation:

We have the following exponential equation

3^{x+1}=15

We must solve the equation for the variable x

To clear the variable x apply the log_3 function on both sides of the equation

log_3(3^{x+1})=log_3(15)

Simplifying we get the following:

x+1=log_3(15)

To simplify the expression log_3 (15) we apply the base change property

log_b(y)=\frac{log(y)}{log(b)}

This means that:

log_3 (15)=\frac{log(15)}{log(3)}

Then:

x+1=\frac{log(15)}{log(3)}

x=\frac{log(15)}{log(3)}-1

x=1.469743

6 0
2 years ago
The expression <img src="https://tex.z-dn.net/?f=%28%20x%5E%7B1%2F2%7Dy%5E%7B-2%2F3%7D%29%5E-6%20%20" id="TexFormula1" title="(
forsale [732]
Y ^(-2/3)^-6 = y^12/3 = y^4

x^(1/2)^ -6 = x^-3 = 1 x^3

so the answer is y^4 * 1 /x^3  = y^4 / x^3

A
8 0
3 years ago
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