The 90% , 99% confidence interval for the population mean is 32.145 < 
< 35.855 and 31.093 < < 36.907
<h3>What is Probability ?</h3>
Probability is the study of likeliness of an event to happen.
It is given that
Total Population = 50
Mean = 35
The confidence interval is given by
is the mean
z is the confidence level value
s is the standard deviation
n is the population width
(a) The 90% confidence interval for the population mean
90% 
= 0.05
Z = 1.64
34 
1.64 * 8 / √50
34 1.855
32.145 < < 35.855
(b) The 99% confidence interval for the population mean
99% = 0.005
Z=2.57
34 2.57 * 8 / √50
34 2.907
31.093 < < 36.907
Therefore the confidence interval for population mean has been determined.
The complete question is
A simple random sample of 50 items from a population width =7 resulted in a sample mean of 35. If required, round your answers to two decimal places.
a. Provide a 90% confidence interval for the population mean
b. Provide a 99% confidence interval for the population mean
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40/3. You mutiply top and bottom straight across, then simplify.
Answer:
n = 2
Step-by-step explanation:
2n - 8 = -2 (-3n + 12) + 8
2n - 8 = -(-6n + 24) + 8
2n - 8 = 6n - 24 + 8
2n - 8 = 6n - 16
-4n = -8
Divide each side by 4
n = 2
The answer to -2(x-8) is 16-2x
The team-lead gets $2000 if the team of 3 QA testers and l QA team lead is working on a project. The team finishes the job and is paid.
<h3>What is average?</h3>
It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.
Let's suppose the team lead salary is x and the team-lead receives, $600 more than the average salary of the entire team then,
The team lead salary:
4x = 3600+ x+ 2400
3x = 6000
x = $2000
Thus, the team lead gets $2000 if the team of 3 QA testers and l QA team lead is working on a project. The team finishes the job and is paid.
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