What is 1/5 - 3/4 thank you for your answer btw I am on edg

Mathematics

2 answers:

Svet_ta [14]3 years ago

5 0

Answer:

- 11/20

-0.55

Step-by-step explanation:

PLZ MRAK ME BRAINLIEST

vitfil [10]3 years ago

3 0

Answer:

-11/20 or -0.55

Step-by-step explanation:

1/5 = 4/20

3/4 = 15/20

4/20 - 15/20 = -11/20

You might be interested in

The equation $(x - 7)^2 + (y + 13)^2 = 12$ represents a circle. What is its radius?

miskamm [114]

Answer:

Step-by-step explanation:

The standard equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

(a, b) is the center of the circle

r is the radius of the circle

Given the equation (x - 7)^2 + (y + 13)^2 = 12

On comparing;

r² = 12

Take the square root of both sides

√r² = √12

r = √12

r = √4*3

r = 2√3

Hence the radius of the circle is 2√3

7 0

3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$