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polet [3.4K]
3 years ago
11

Write the equation of a line with the given slope and y intercept. m = 4 b = -2​

Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer: y=4x-2

Step-by-step explanation:

Use the y=mx+b template to write the equation out. M is the slope which should be in front of x. This is why y=4x-2 is correct

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Which of these ratios are equivalent ratio<br> 1:4 2:8 3:6 7:28
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Answer:

1:4

2:8

7:28

Step-by-step explanation:

  • 1:4
  • 2:8 , 1:4
  • 7:28, 1:4
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Margie's car can go 3232 miles on a gallon of gas, and gas currently costs $4$4 per gallon. How many miles can Margie drive on $
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Find the value of (-15/8 + 1.5) = (15 – 14 3/4)? *<br> -3/2<br> 0 -3/32<br> O 3/32<br> O 3/2
sukhopar [10]

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Step-by-step explanation:

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2 years ago
What is the slope of the line that passes through (-4, 6) and (-6, 20)?
Hatshy [7]

Answer:

-7

Step-by-step explanation:

Since we have two points, we can use the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 20-6)/(-6- -4)

    = ( 20-6)/ ( -6+4)

    = 14/-2

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3 0
2 years ago
Solve The Equation <br> 4x×9y=7<br> 4x-9y=9
hoa [83]

Answer:

\large\boxed{x=\dfrac{9}{8}-\dfrac{\sqrt{109}}{8},\ y=-\dfrac{1}{2}-\dfrac{\sqrt{109}}{18}}\\or\\\boxed{x=\dfrac{9}{8}+\dfrac{\sqrt{109}}{2},\ y=-\dfrac{1}{2}+\dfrac{\sqrt{109}}{18}}

Step-by-step explanation:

\left\{\begin{array}{ccc}4x\times9y=7&(1)\\4x-9y=9&(2)\end{array}\right\\\\(2)\\4x-9y=9\qquad\text{subtract}\ 4x\ \text{from both sides}\\-9y=-4x+9\qquad\text{change the signs}\\9y=4x-9\qquad\text{substitute it to (1)}\\\\4x(4x-9)=7\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\(4x)(4x)+(4x)(-9)=7\\(4x)^2-36x=7\\(4x)^2-2(4x)(4.5)=7\qquad\text{add}\ 4.5^2\ \text{to both sides}\\(4x)^2-2(4x)(4.5)+4.5^2=7+4.5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2

(4x-4.5)^2=7+20.25\\(4x-4.5)=27.25\to 4x-4.5=\pm\sqrt{27.25}\\\\4x-\dfrac{45}{10}=\pm\sqrt{\dfrac{2725}{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{2725}}{\sqrt{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25\cdot109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25}\cdot\sqrt{109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{5\sqrt{109}}{10}\qquad\text{add}\ \dfrac{45}{10}\ \text{to both sides}\\\\4x=\dfrac{45}{10}\pm\dfrac{5\sqrt{109}}{10}

4x=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 4}\\\\x=\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\\\\\text{Put the values of}\ x\ \text{to (2):}\\\\9y=4\left(\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\right)-9\\\\9y=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}-\dfrac{18}{2}\\\\9y=-\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 9}\\\\y=-\dfrac{1}{2}\pm\dfrac{\sqrt{109}}{18}

8 0
3 years ago
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