Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
A compound event, I believe
Answer:
Scott will have to do 44 practices
Step-by-step explanation:
Let X be the number of yards per practice.
Let P = number of practice Scott needs to do.
Multiply 20 yards by 4 sprints
X = 20yards × 4 sprints = 80 yards
Number of yards he had to sprint per practice will be:
1 mile = 1760 yards
Converting from miles to yards
X = 1760 × 2 miles = 3520 yards
Number of practice,P Scott need to do = (3520/80)yards
Number of Practice,P = 44
Answer:
circle
Step-by-step explanation:
Hi there! :)
Answer:
Given the information, we can write an equation in slope-intercept form
(y = mx + b) to graph the line:
Plug in the slope for 'm', the y-coordinate of the point given for 'y', and the
x-coordinate given for 'x':
-4 = -2/3(-7) + b
-4 = 14/3 + b
Solve for b:
-12/3 = 14/3 + b
-12/3 - 14/3 = b
-26/3 = b
Therefore, the equation of the line is y = -2/3x - 26/3 (Graphed below)
Some points on the line include:
(-7, -4)
(-4, -6)
(0, -26/3)
(2, -10)
(5, -12)
