Answer:
J) is multiplied by 4
Step-by-step explanation:
Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
Answer:
32 divided by 4 = 8,
8^2 + 8^2 = 128
128: 11^2 = 121 close enough, 11 is your answer
We are finding hypotenuse but first we find the length of all sides of the two squares to find the two sides of the triangle then we find hypotenuse.
Answer:
73.5
Step-by-step explanation:
circumference = 2πr , where r = radius
given radius = 11.7 so r = 11.7
C = 2πr
==> plug in r = 11.7
C = 2π(11.7)
==> multiply 2 and 11.7
C = 23.4π
==> multipl 23.4 and π
C = 73.5 ( rounded to the nearest tenth )
Answer:
=0.56184
Step-by-step explanation:
