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guapka [62]
3 years ago
6

A park maintenance person stands 16m from a circular monument. Assume that her lines of sight form tangents to the monument and

make an angle of 56 degrees. What is the measure of the arc of the monument that her lines of sight intersect?
Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

The arc subtends a central angle of 124°

You might be interested in
Which equation shows the ratios of the number of people who attended the high school musical to
sweet-ann [11.9K]

Answer:

45:27 , 27:9 ,  45:9 , 45:15,

:Step-by-step explanation:

which ever one is on there

4 0
3 years ago
Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a
NARA [144]

x^3y^2+\sin(x\ln y)+e^{xy}=0

Differentiate both sides, treating y as a function of x. Let's take it one term at a time.

Power, product and chain rules:

\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}

=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}

=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}

Product and chain rules:

\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}

=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)

=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)

=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}

Product and chain rules:

\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}

=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)

=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)

=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0

Isolate the derivative, and solve for it:

\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by y to get rid of that fraction in the denominator.

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}

3 0
3 years ago
What is 5/6 - 5/54 in simplest form
Fiesta28 [93]
Make bottom number same
6 and 54
common muultiplie is 54
multiply 5/6 by 9/9
45/54-5/54=(45-5)/54=40/54=20/27
6 0
3 years ago
What is the largest power of 2 that is a divisor of 13^4 - 11^4?
OverLord2011 [107]

Answer:

2^5

Step-by-step explanation:

Given:

(13^4 - 11^4)(13^2+11^2)

add all together with exponents

=48*290

= Then turn into a smaller exponent

= 2^4 * 3 * 2*145

combine like terms

2^4 *2

=2^5

5 0
2 years ago
Read 2 more answers
144=12x <br> 45 =4x-27 <br> 2x-2=14 <br> 12x=44-10x does any one kno these questions?
Free_Kalibri [48]

Hello russell6333!

\huge \boxed{\mathfrak{Question} \downarrow}

Solve for x.

  1. 144 = 12x
  2. 45 = 4x - 27
  3. 2x - 2 = 14
  4. 12x = 44 - 10x

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

1) \:  \:  \: 144 = 12x \\  \frac{144}{12}  = x \\ \boxed{ \boxed{  \bf12 = x}}

__________________

2) \:  \:  \: 45 = 4x - 27 \\ 45 + 27 = 4x \\ 72 = 4x \\  \frac{72}{4}  = x \\  \boxed{ \boxed { \bf18 = x }}

__________________

3) \:  \:  \: 2x - 2 = 14 \\ 2x = 14 - 2 \\ 2x = 12 \\ x =  \frac{12}{2}  \\ \boxed{  \boxed{ \bf \: x = 6}}

__________________

4) \:  \:  \: 12x = 44 - 10x \\ 12x + 10x = 44 \\ 22x = 44 \\ x =  \frac{44}{22}  \\  \boxed{\boxed{  \bf \: x = 2}}

__________________

<h3><u>NOTE </u><u>:</u><u>-</u></h3>
  • To solve questions of these sorts, bring all the terms to one side & simplify it leaving x alone in the other side of the equation (other side of the equal to sign). After simplification you'll get the value of x.
  • Remember that the signs & operations will change when you bring a term to the other side of the equation.
  • So, addition will become subtraction, subtraction will become addition, multiplication will become division & division will become multiplication.

__________________

Hope it'll help you!

ℓu¢αzz ッ

8 0
3 years ago
Read 2 more answers
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