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borishaifa [10]
3 years ago
8

If you have 45 dollars and you lose 2 thirds in 6 hours how much money do you have left

Mathematics
1 answer:
Nady [450]3 years ago
8 0
Multiply 45 by 2/3 2/3 = 0.66666   so 45*0.6666 = 30
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djyliett [7]

Answer:

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Step-by-step explanation:

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2 years ago
Write the equation of the line that has the slope m=2/5 and passes through the point ​(25​,−9​). Write the equation in​ slope-in
klemol [59]
You're given the slope of the line and a point thru which the line passes.  So it makes sense to use the point-slope form of the equation of a straight line:  if the point is (a,b) and the slope is m, then 

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8 0
3 years ago
35% of what number is 91
Aleonysh [2.5K]

Answer:

3185

Step-by-step explanation:

4 0
3 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
Can someone help me
kakasveta [241]

Answer:

a. 2*-2*3=-12

b. -2*3*5 = -30

c. (-2)^2+2*5= 14

d. 2*-2+3*3-5*5= -20

e. -2(3-5) = 4

f. 3*5-(-2)*5+(-2)*3 = 19

if it helped then plz mark me as brainliest

8 0
3 years ago
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