3 years ago

Line that passes through (-2,1) and (4,13)

Mathematics

1 answer:

Delvig [45]3 years ago

6 0

Whats the question??

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(X-1)×(x-2)

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elena-s [515]

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Step-by-step explanation:

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Solution 2^2x+3-7(2^2x+1)+3=0 introduce Log

Andrej [43]

Answer:

$x = \frac{log\sqrt{-1/6}}{log2}$

Step-by-step explanation:

Given the expression

$2^{2x}+3-7(2^{2x}+1)+3=0$

Let $P=2^x$

Substituting into the expression, we will have:

$P^2+3-7(P^2+1)+3=0\\Expand\\P^2+3-7P^2-7+3=0\\-6P^2-1=0\\6P^2=-1\\p^2=-1/6\\P=\sqrt{-1/6}$

Since:

$P=2^x\\2^x=\sqrt{-1/6}\\xlog2=log(\sqrt{-1/6}) \\x = \frac{log\sqrt{-1/6}}{log2}$

7 0

3 years ago