This is an incomplete question.
Surface area of a cube is given by
SA=6a²
but
SA=150 in²
thus
150=6a²
solving for a we obtain:
150/6=a²
a²=25
thus
a=√25
a=5 inches
hence the side length is 5inches
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Answer:
g(1) =7
Step-by-step explanation:
g(x) = 2x + 5
Let x=1
g(1) = 2(1) +5
= 2+5
=7
Answer:
<I= 15degrees
Step-by-step explanation:
Using the cosine rule formulae;
j² = i²+k²-2i cos <J
j² = 37²+57² - 2(37)(57)cos <141
j² = 1369+ 3249- 4218cos <141
j² = 4618- 4218cos <141
j² = 4618-(-3,278)
j²= 7,896
j = √7,896
j = 88.86inches
Next is to get <I
i² = j²+k²-2jk cos <I
37² = 88.86²+57² - 2(88.86)(57)cos <I
1369 = 7,896.0996+ 3249- 10,130.04cos <I
1369 = 11,145.0996 - 10,130.04cos <I
1369 - 11,145.0996 = - 10,130.04cos <I
-9,776.0996=- 10,130.04cos <I
cos <I =9,776.0996 /10,130.04
cos<I = 0.96506
<I = 15.19
<I= 15degrees