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Paraphin [41]
2 years ago
13

PLEASE HELP I WILL GIVE BRAINLIEST!!!!

Mathematics
1 answer:
Vladimir79 [104]2 years ago
6 0

Answer: Let's solve for x.

2x−10y=10

Step 1: Add 10y to both sides.

2x−10y+10y=10+10y

2x=10y+10

Step 2: Divide both sides by 2.

2x

2

=

10y+10

2    answer

    x=5y+5

Step-by-step explanation:

Let's solve for s.

sx+9y=9

Step 1: Add -9y to both sides.

sx+9y+−9y=9+−9y

sx=−9y+9

Step 2: Divide both sides by x.

sx

x

=

−9y+9

x

s=

−9y+9

x

Answer:                         hope this helps:)

s= -9y+9/x

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 To get the answer do this: 

2.5% of what is 2.21

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Answer:

z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

p_v =P(Z  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=4.6 represent the sample mean

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\alpha=0.1 represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if thetrue mean is below the specifications, the system of hypothesis would be:  

Null hypothesis:\mu \geq 4.8  

Alternative hypothesis:\mu < 4.8  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

P-value

Since is a one sided test the p value would be:  

p_v =P(Z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

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Use the same method for your problem 5 feet divided by 6 is 0.83 feet per piece.

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1

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