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3 years ago

Helllllpllppppppppp there are 2 pics

Mathematics

2 answers:

horrorfan [7]3 years ago

4 0

There are no pics. Sorry :(

OLga [1]3 years ago

3 0

Answer:

picsssssssss wht ahhh jajajkihskai

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A stone is launched off a building which is 95 feet high. Its height at time t is given by the function h(t) = 95 + 10t − 4t2 wh

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the median of this list of numbers? 22, 18, 23, 36, 26, 18, 29. A. 22 B. 18 C. 23 D. 36

7nadin3 [17]

Answer:

C. 23

Step-by-step explanation:

18 18 22 23 26 29 36

23 is in the middle

5 0

3 years ago

Fine the slope of the line through each pair of points . (-8,-20),(5,2)

kozerog [31]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-8, -20) and (5, 2). Substitute:

$m=\dfrac{2-(-20)}{5-(-8)}=\dfrac{22}{13}$

Answer: The slope is $\dfrac{22}{13}$

7 0

4 years ago

Read 2 more answers

Asap I will fail it’s due soon

Elan Coil [88]

Answer:

See explanation

Step-by-step explanation:

1. From the graph of absolute value function:

a. The domain is $x\in (-\infty, \infty)$

b. The range is $y\in [0,\infty)$

c. The graph is increasing for all $x>0$

d. The graph is decreasing for all $x$

2. From the graph of quadratic function:

a. The domain is $x\in (-\infty, \infty)$

b. The range is $y\in (-\infty,0]$

c. The graph is increasing for all $x$

d. The graph is decreasing for all $x>0$

4 0

3 years ago

It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha

stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

0.54% of the calls receive a busy signal, hence p = 0.0054.

A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

$P(X \geq 5) = 1 - P(X < 5)$

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009$

$P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062$

$P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218$

$P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513$

$P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903$

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295$

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

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6 0

2 years ago