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forsale [732]
2 years ago
15

Find AM in the parallelogram if PN=10 and AO=5 a 5 b 10 c 5 d 10

Mathematics
1 answer:
Tresset [83]2 years ago
8 0

Answer:

the diagram is not a scale

Step-by-step explanation:

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Determine if the following side lengths could form a triangle.
kykrilka [37]

Answer: Determine if the following side lengths could form a triangle.

Prove your answer with an inequality.

8,17,24

Step-by-step explanation:

Determine if the following side lengths could form a triangle.

Prove your answer with an inequality.

8,17,24

4 0
2 years ago
In ΔXYZ, z = 81 cm, ∠Y=139° and ∠Z=6°. Find the length of y, to the nearest 10th of a centimeter.
Delicious77 [7]

Answer:

508.4

Step-by-step explanation:

This is on delta math

3 0
3 years ago
Read 2 more answers
Please provide an answer
Igoryamba

Answer:

Step-by-step explanation:

The opposite angles in a quadrilateral theorem states that when a quadrilateral is inscribed in a circle, the angles that are opposite each other are supplementary, their degree measures add up to 180 degrees. One can apply this here by using the sum of (<C) and (<A) to find the measure of the parameter (z). Then one can substitute in the value of (z) to find the measure of (<B). Finally, one can use the opposite angles in a quadrilateral theorem to find the measure of angle (<D) by using the sum of (<B) and (D).

Use the opposite angles in an inscribed quadrialteral theorem,

<A + <C = 180

Substitute,

14x - 7 + 8z = 180

Simplify,

22z - 7 = 180

Inverse operations,

22z = 187

z = \frac{187}{22}

Simplify,

z = \frac{17}{2}

Now substitute the value of (z) into the expression given for the measure of angle (<B)

<B = 10z

<B = 10(\frac{17}{2})

Simplify,

<B = 85

Use the opposite angles in an inscribed quadrilateral theorem to find the measure of (<D)

<B + <D = 180

Substitute,

85 + <D = 180

Inverse operations,

<D = 95

8 0
2 years ago
Read 2 more answers
5y-x=10 solve for y
shusha [124]
5y-x=10\\\\ 5y=10+x \ |:5 \ Both \ sides \\\\ y=\frac{10}{5}+\frac{x}{5}\\\\ y=2+\frac{x}{5}

because
5y-x=5(2+\frac{x}{5})-x=5\cdot 2 +\frac{x}{\not5}\cdot 5 - x= 10+x-x=10



3 0
3 years ago
3x + x + x + x − 3 − 2 = 7 + x + x In the equation above, what is the value of x? A) −5 7 B) 1 C) 12 7 D) 3
oksano4ka [1.4K]

Answer:

x=3

Step-by-step explanation:

3x + x + x + x − 3 − 2 = 7 + x + x

Combine like terms

6x -5 = 7+2x

subtract 2x from each side

6x-2x -5 = 7+2x-2x

4x -5 = 7

Add 5 to each side

4x-5 +5 = 7+5

4x =12

Divide by 4

4x/4 =12/4

x=3

6 0
3 years ago
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