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forsale [732]
3 years ago
15

Find AM in the parallelogram if PN=10 and AO=5 a 5 b 10 c 5 d 10

Mathematics
1 answer:
Tresset [83]3 years ago
8 0

Answer:

the diagram is not a scale

Step-by-step explanation:

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Can someone please help me?! Marking Brainliest!!!!!
irga5000 [103]

Answer:

5\sqrt{2}

Step-by-step explanation:

The formula for the length of a vector/line in your case.

L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}

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The image of trapezoid ABCD has coordinates A'(-2,-5), B'(-1, -2), C'(2,-2), and D'(3,-5). It was translated by the
dolphi86 [110]

Answer:

A

Step-by-step explanation:

JUST TOOK THE TEST

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3 years ago
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Your favorite restaurant offers a total of 14 desserts, of which 8 have ice cream as a main ingredient and 12 have fruit as a ma
djyliett [7]
Your favorite restaurant offers a total of 13 desserts, of which 11 have ice cream as a main ingredient and 9 have fruit as a main ingredient. Assuming that all of them have either...
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4 years ago
Can someone please answer. There is one problem. There's a picture. Thank you!
julia-pushkina [17]
A=\pi\cdot (2.5)^2=6.25\pi\approx19.63
7 0
3 years ago
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PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!
irga5000 [103]

Answer:

None of these.

Step-by-step explanation:

Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem.  So we know (x-6) is not a factor because the remainder wasn't zero.

Let's assume we are trying to figure out if (x^2+6) is a factor.  The quotient is (x-6) and the remainder is 13 according to the problem.  So we know (x^2+6) is not a factor because the remainder wasn't zero.

In order for 13 to be a factor of P, all the terms of P must be divisible by 13.  That just means you can reduce it to a form that is not a fraction.

If we look at the first term x^3 and we divide it by 13 we get \frac{x^3}{13} we cannot reduce it so it is not a fraction so 13 is not a factor of P

None of these is the right option.

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3 years ago
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