Answer:
51 were the total number of the tickets sold at a school carnival were early-admission tickets.
Step-by-step explanation:
Total number of tickets sold by = 100
Let 
be the early-admission tickets sold by the school.
As 51% of the tickets sold at a school carnival were early-admission tickets.
so
Therefore, 51 were the total number of the tickets sold at a school carnival were early-admission tickets.
Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
Here is your answer:
Your answer is 18%
Reason: That's because 18 has a invisible decimal point:
18.
Then you move to decimal and change it into a %
Which will make it 18%
Your answer is...
18%
Answer: (9,-10) or x=9...y=-10
