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3 years ago

What is the radius of the following circle?

Mathematics

2 answers:

lara [203]3 years ago

7 0

Answer:

The radius is: $2\sqrt{3}$

Step-by-step explanation:

The equation of a circle in center-radius form is:

$(x - h)^2 + (y - k)^2 = r^2$

Where the center is at the point (h, k) and the radius is "r".

So, given the equation of the circle:

$x^2+y^2=12$

You can identify that:

$r^2=12$

Then, solving for "r", you get that the radius of this circle is:

$r=\sqrt{12}\\\\r=2\sqrt{3}$

lutik1710 [3]3 years ago

6 0

Answer:

r = +2√3

Step-by-step explanation:

The equation of a circle with center at (0, 0) and radius r is

x^2 + y^2 = r^2.

Here we have

x^2 + y^2 = 12,

and so we can deduce that r^2 = 12. Then r = +2√3.

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B is between A and C. AB = 3x, BC = 2x + 7, AC = 42 a) X = b)AB = c)BC=

ryzh [129]

Answer: x=7

ab=21

bc=14

Step-by-step explanation:

ab=3x

bc=2x±7

ac=42

3x±2x±7=42

5x±7=42

5x=42-7

5x=35

to get the value of x you divide 35 by 5x

35÷5x=7

so the value of x is 7

ab=3x

x=7

3x=7×3x

7×3=21

x=7

2x=7×2x

2×7=14

5 0

2 years ago

An engineer measures the peak current (in microamps) when a solution containing an amount of nickel (in parts per 106 ) is added

dangina [55]

Answer:

B. decrease the intercept, increase the slope

Step-by-step explanation:

A slope indicates the steepness of a line while the intercept points the location where it intercepts its axis. The linear relationship between can be defined using the intercept and the slope. Both concepts are used to estimate the average range of change. Since we are trying to add a peak current value of 0.38 which is lesser than the average, the intercept of the graph would therefore decrease and the slope increase.

7 0

2 years ago

A fountain, 3 ft in diameter, sits in the center os a circular duck pond. The pond measures 3 ft from the fountain to its edge.

umka2103 [35]

Answer:

$56.55\ ft^2$

Step-by-step explanation:

We know that the diameter of the fountain is 3 feet and that it is in the center of the pond.

We know that the area of a circumference is:

$\pi(r)^2$

where r is the radius of the circumference.

further

d = 2r

Where d is the diameter of the circumference.

Then the radius $r_1$ of the source is 1.5 ft.

The radius $r_2$ of the pond is 1.5 + 3 = 4.5 ft

Finally the area of the pond is equal to the area of the ring that is shown in the image

$A = \pi(r_2)^2 - \pi (r_1)^2\\\\A = \pi(4.5)^2 - \pi(1.5)^2\\\\A = \pi(4.5^2 - 1.5^2)\\\\A = 18\pi = 56.55\ ft^2$

5 0

2 years ago

Step by step workout of ; log x^3+log 5x=5 log 2-log 2/5

Charra [1.4K]

Answer:

x = 2

Step-by-step explanation:

$log \: {x}^{3} + log \: 5x = 5log \: 2 - log \: \frac{2}{5} \\ \\ \therefore \: log( {x}^{3} \times 5x) = log {2}^{5} - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log 32 - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(32 \times \frac{5}{2} \bigg) \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(16 \times 5) \\ \\ \therefore \: 5{x}^{4}= 16 \times 5 \\ \\ \therefore \: {x}^{4}= {2}^{4} \\ \\ \huge \purple{ \boxed{\therefore \: {x} = 2}}$