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2 years ago

What is the area of the rectangle if the sides are 7 and 5?

Mathematics

2 answers:

topjm [15]2 years ago

7 0

Answer:

35 units

Step-by-step explanation:

To find the area of a rectangle, you must multiply the length and width, which is in this case seven and five. 7 times 5 = 35.

Fiesta28 [93]2 years ago

5 0

Answer: 35

Step-by-step explanation:

To work out the area of a rectangle you just have to times the sides (the base times the height).

7×5=35

Hope this helps :)

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15 points help! Select the correct answer from the drop-down menu.

Leokris [45]

Answer:The value of m for the given equation is, 35

Step-by-step explanation:

Given an equation: https://tex.z-dn.net/?f=x%5E%7B3m%7D%3D(x%5E%7B65%7D)*(x%5E%7B40%7D)

Use the above property on RHS in equation [1];

Since the base are same i.e, x ; we can add the exponents.

Using: , then a=b.

Therefore, 3m=105.

Divide 3 on both sides of an equation:

Simplify:

m=35

Therefore, the valur of m is, 35.

6 0

2 years ago

Please help i’ll mark brainlest!!!!!

vitfil [10]

The answer to your question should be b

7 0

3 years ago

1.688 × 10⁴ = write in standard format

Neporo4naja [7]

Answer

16880

Step-by-step explanation:

10x10x10x10=10,000

1.688x10,000=16880

hope that helps

7 0

3 years ago

Read 2 more answers

The sum of two segments are 75 cm, and one the segments are four times the other. Calculate the measurement of each segment

iVinArrow [24]

The length of one segment is 15 cm and other segment is 60 cm

Step-by-step explanation:

Let x be the length of one segment and y be the length of other segment

Then according to given statement

x+y=75 Eqn 1

And

one the segments are four times the other

x=4y Eqn 2

$Putting\ x=4y\ in\ equation\ 1$

$4y+y=75\\5y=75\\Dividing\ both\ sides\ by\ 5\\\frac{5y}{5}=\frac{75}{5}\\y=15\\Putting\ y=15\ in\ eqn\ 2\\x=4(15)\\x=60$

Hence,

The length of one segment is 15 cm and other segment is 60 cm

Keywords: Linear Equation, Variables

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

a surveyor measures the distance to the two landmarks as shown in the diagram what is the distance d. between the landmarks

Inessa [10]

<h3>The distance between two landmarks is 123 meters</h3>

<em><u>Solution:</u></em>

We have to find the distance between two landmarks

<em><u>Use the law of cosines</u></em>

The third side of a triangle can be found when we know two sides and the angle between them

$c^2 = a^2 + b^2 - 2ab\ cos c$

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

c = d

Therefore,

$d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123$

Thus, the distance between two landmarks is 123 meters

8 0

3 years ago