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ch4aika [34]
3 years ago
14

Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s

uperficie es de 0.6 . Determine la aceleración resultante en m/s2 que lleva el bloque aproximando el resultado a las décimas.
Mathematics
1 answer:
ozzi3 years ago
8 0

Answer:

10.9\ \text{m/s}^2

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

\mu = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2

La aceleración del bloque es 10.9\ \text{m/s}^2.

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