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jonny [76]
2 years ago
12

I badly want the answer to these☠️​

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
5 0

Step-by-step explanation:

1. 4/10 + 15/10

The two fractions have like denominators so you can add the numerators.

Then:

4+15/10=19/10

This fraction cannot be reduced.

The fraction

19/10

is the same as

19÷10

Convert to a mixed number using

long division for 19 ÷ 10 = 1R9, so

19/10=19/10

Therefore:

4/10+15/10=1 9/10

2. 50/20+60/20=5 1/2

3. \sf \frac{60}{40}  +  \frac{80}{40} = 3 \frac{1}{2}

4. \sf\frac{90}{60}  +  \frac{80}{60} = 2 \frac{5}{6}

5. \sf \frac{120}{40}  +  \frac{80}{40} = 5

6. \sf \frac{120}{40}  +  \frac{140}{40} = 6 \frac{1}{2}

7. \sf \frac{110}{70}  +  \frac{40}{70} = 2 \frac{1}{7}

8. \sf \frac{45}{5}  +  \frac{60}{5} = 21

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Determine any data values that are missing from the table, assuming that the data represent a linear function.
posledela

Answer:

  • d. Missing x:11 Missing y:19​

Step-by-step explanation:

<u>It can be determined that the function is:</u>

  • y = 0.5x + 12.5

<u>So missing x is:</u>

  • 18 = 0.5x + 12.5 ⇒ 0.5x = 5.5 ⇒ x = 11

<u>Missing y is:</u>

  • y = 13*0.5 + 12.5 = 19

<u>Missing numbers are:</u>

  • x= 11 and y = 19

Correct choice is d.

3 0
3 years ago
Read 2 more answers
A: (0, –t)<br><br> B: (0, r)<br><br> C: (t, 0)<br><br> D: (–r, 0)
adell [148]
D should be the right answer
7 0
3 years ago
A new school has x day students and y boarding students.
guapka [62]

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as x + 2y\geq 1200.​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are \$600 a term.

So, the fees for x day students are \$600x a term.

The fees for a boarding student are \$1200 a term.

The fees for y boarding student are \$1200y a term.

Total fees for x day students and y boarding student is:

\text{Total fees}=600x+1200y

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

600x+1200y\geq 720000

600(x+2y)\geq 720000

Divide both sides by 600.

\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}

x+2y\geq 1200

Hence proved.

3 0
3 years ago
Solve photo question, please. Second.
Ivan
Hello,
Here is the graph (6,2) is the answer

7 0
3 years ago
Simplify <br> 1) 3b + b + 6 =<br> 2)n + 5n - 3c =<br> 3) 12d - 2d + e =
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1. 4b plus 6
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4 years ago
Read 2 more answers
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