Answer:
The minimum sample size required is 4610.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:
The margin of error for this interval is:
It is provided that a 99% confidence interval is computed to estimate the percentage of homeowners who own at least two television sets.
Assume that 50% of the homeowners own at least two television sets.
So, the sample proportion is, .
The critical value of <em>z</em> for 99% confidence interval is:
*Use a <em>z</em>-table for the critical value.
The margin of error is given as, MOE = 0.019.
Compute the value of <em>n </em>as follows:
Thus, the minimum sample size required is 4610.