Part A: 5 is the coefficient, w is the variable, 50 is the constant
Part B: 10 x 5 = 50 + 2 x 20 = 40+ 50 = $140
Part C: the constant,50,would change and become 85. Hope this helps :)
Answer:
The maximum volume of space that 1,000 BTUs will cool is 400 cubic foot.
Step-by-step explanation:
Given : A total of 1,000 BTUs are needed to cool a space. If 2.5 BTUs are needed to cool 1 cubic foot of space.
To find : What is the maximum volume of space that 1,000 BTUs will cool?
Solution :
Applying unitary method,
2.5 BTU are needed to cool 1 cubic foot of space.
So, 1 BTU are needed to cool 
cubic foot of space.
Then,1000 BTU are needed to cool 
cubic foot of space.
i.e. 1000 BTU are needed to cool 400 cubic foot of space.
Therefore, the maximum volume of space that 1,000 BTUs will cool is 400 cubic foot.
Answer:5 worker can 60 widget in 90 minutes.
Answer:
36
Step-by-step explanation:
The formula of LCM is LCM(a,b) = ( a × b) / GCF (a,b)
The Greatest Common Factor of (9,12) = 3
Therefore
LCM of 9 and 12 = (9 × 12) / 3
= 108/3 = 36
LCM of 9 and 12 = 36
Irrespective of the method, the solution to our question LCM of 9 and 12 is the same.
Therefore, LCM of 9 and 12 is 36
Answer:
Step-by-step explanation:
Arrival rate = ∧ = 2.2 customers per hour
Service rate = u = 5 customers per hour
1. Probability that one customer is receiving a haircut and one customer is waiting
P(2 customers)=(∧/u)^2 * (1-∧/u)=(2.2/5)^2 * (1-2.2/5)=0.1936*0.56= 0.108416
2. Probability that one customer is receiving a haircut and two customers are waiting
P(3 customers)= (∧/u)^3 * (1-∧/u)=(2.2/5)^3 * (1-2.2/5)= 0.085184
* 0.56= 0.04770304
3. Probability that more than two customers are waiting
P(more than 3 customers)=1- P(less than 3 customers) =
1- [P(0)+P(1)+P(2)+P(3)]=
= 1- [(1-2.2/5) +2.2/5*(1- 2.2/5) + 0.108416+0.04770304]=1-0.9625=0.0375
3. Probability that more than two customers are waiting =
