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AlekseyPX
3 years ago
5

A person leaves home at 8:00 a.m. and drives to a destination at a rate of 40 mph. The person returns at a rate of 25 mph and ar

rives at 2:30 p.m. How far was the destination?
65 miles
100 miles
130 miles
Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0
100 miles... like I said before. Hope u do good on ur assignment/quiz ... :/
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Divide. Use​ place-value blocks or area models to help.
Shalnov [3]

Answer:

a 5,900÷90=65.5555555556

5 0
3 years ago
A student fond the slope of a line that passes through the points (-8,-6) and (2,-3) to be 3/10. what mistake did she make?
goldfiish [28.3K]
Simple ....

we know to find slope is (y1-y2)/(x1-x2)

if we plug in what we know......

(-8,-6),(2,-3)

(-6--3)/(-8-2)

it turns into...

(-6++3)/(-8+-2)

(-3)/(-10)= 3/10

Thus, your answer is that she made no mistake. (C)
4 0
3 years ago
Please help me now plz <br> I will mark you brainliest
s2008m [1.1K]

Answer:

theta = 24.4 degrees

Step-by-step explanation:

This is a right triangle.

sin theta = opp/ hyp

sin theta = 33/80

Take the inverse of each side

sin^-1 sin(theta) = sin^-1 (33/80)

theta =24.36197794

To the nearest tenth

theta = 24.4 degrees

7 0
3 years ago
Plz with steps .. it's very hard can anyone plz
liubo4ka [24]

Answer:

Step-by-step explanation:

\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a}  \qquad  f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a}  \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}}  }{\dfrac{1}{2\sqrt{x}} }\\\\

\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}  =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\

7 0
3 years ago
The quadratic x^2+440x+440^2 can be written in the form (x+b)^2+c, where b and c are constants. What is c/b?
Sauron [17]
This form (x+b)²+c is a vertex form that can be found by completing square for the equation <span>x²+440x+440².

To complete square we will need to use formula  a² +2ab + b² = (a+b)²

</span> x²+440x+440²,
<span>x² +2*220²x +220² -220² +440²  (we added </span>220² -220², so nothing really changed here).

x² +2*220²x +220² -220² +440² ( here , bold part can be rewritten as (x+220)²)

(x+220)² -220² +440² (calculating bold part)<span>
 
</span>(x+220)² -220² +440² = (x+220)²  + 145200

Now we have  x²+440x+440², in the form that we need 
 x²+440x+440² = (x+220)²  + 145200

(x+b)²+c = (x+220)²  + 145200,
b=220,
c= 145200

So, 
c/b = 145200/220 = 660
c/b = 660/1 (if you need it in a fraction form)  or 660.


7 0
3 years ago
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