W(2) = 2^2 + 2 = 4 + 2 = 6
u(w(2)) = -x -2 = -6 - 2 = -8
answer: u(w(2)) = -8
Answer:
0.4
Step-by-step explanation:
Let X be the random variable that represents the number of consecutive days in which the parking lot is occupied before it is unoccupied. Then the variable X is a geometric random variable with probability of success p = 2/3, with probability function f (x) = [(2/3)^x] (1/3)
Then the probability of finding him unoccupied after the nine days he has been found unoccupied is:
P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9). For a geometric aeatory variable:
P (X> = 10) = 1 - P (X <10) = 0.00002
P (X> = 9) = 1 - P (X <9) = 0.00005
Thus, P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9) = 0.00002 / 0.00005 = 0.4.
The tangent and cotangent functions of the angle are related such that one is the reciprocal of the other. From the given tan theta = 11 / 60. The reciprocal of this number is 60 / 11. This value is also the cotangent of the angle. Thus, the cotangent angle theta is 60 / 11.
-5w=45
/-5 /-5
w=-9
The answer is -9
