Cube root of 27 a^12 will be: 3 a^4.
Answer:
If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) (0.5)^{t/T} = 400 (0.5)^{t /4}, where T is the half-life period and y(0) is the amount at t = 0 years (initial).
Then at t = 20:
y(20) = 400 (0.5)^{20 /4} = \text{12.5 mg}
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
please mark as brainlist answer
Answer:
8 79/100
Step-by-step explanation:
Answer:
a : b : c = 12 : 10 : 15
Step-by-step explanation:
Given that: b =
of c
i.e b =
............... 1
2c = 5b
So that;
c =
.................... 2
Also,
4a = 3c
a =
................ 3
⇒ a =
× (
)
a =
................. 4
15b = 8a
b =
................. 5
Comparing the derived equations:
From equations 2 and 3,
a:c =
:
= 4:5
From equations 1 and 2,
b:c =
:
= 2:3
But a common value of b = 15, gives;
a : c = 12 : 15 and b : c = 10 : 15
Thus, a : b : c = 12 : 10 : 15