An integer may be a multiple of 3.
An integer may be 1 greater than a multiple of 3.
An integer may be 2 greater than a multiple of 3.
It is redundant to say an integer is 3 greater than a multiple of 3 (that's just a multiple of 3, we've got it covered). Same for 4, 5, 6, 7...
Let's consider a number which is a multiple of 3. Clearly, we can write 3+3+3+3+... until we reach the number. It can be written as only 3's.
Let's consider a number which is 2 greater than a multiple of 3. If we subtract 5 from that number, it'll be a multiple of 3. That means we can write the number as 5+3+3+3+3+... Of course, the number must be at least 8.
Let's consider a number which is 1 greater than a multiple of 3. If we subtract 5 from that number, it'll be 2 greater than a multiple of 3. If we subtract another 5, it'll be a multiple of 3. That means we can write the number as 5+5+3+3+3+3+... Of course, the number must be at least 13.
That's it. We considered all the numbers. We forgot 9, 10, 11, and 12, but these are easy peasy.
Beautiful question.
Answer:
True
Step-by-step explanation:
An input is always anything that equals a sum.
Input: Small-Medium-Large
Output: Prices
Answer:
r = 8,9,10
Step-by-step explanation:
The given inequality is :
5r≤6r−8 ...(1)
We need to find the value of r.
Subtracting 5r to both sides of the inequality .
5r-5r≤6r-5r−8
0≤r−8
r ≥ 8
Hence, the values of r are 8,9,10.
Answer:
The answer is -94 but where is b
Step-by-step explanation:
2(4)-6(17)=-94
