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2 years ago

With one of these is a functionabcd

Mathematics

2 answers:

Liono4ka [1.6K]2 years ago

5 0

Answer:

B is a functional answer

Shalnov [3]2 years ago

3 0

Answer:

It's B

Step-by-step explanation:

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There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin

Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

6 0

3 years ago

PLZ I NEED THE ANSWER RN ASAP PLEASEEE!!!<br><br> Q-Solve for the value of D

enyata [817]

Answer:

uuuuh 7

Step-by-step explanation:

7 0

3 years ago

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th

11111nata11111 [884]

Answer:

The null hypothesis is $H_0: \mu = 14$

The alternate hypothesis is $H_a: \mu < 14$

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

$H_0: \mu = 14$

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

$H_a: \mu < 14$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that $\mu = 14$

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that $n = 40$

Test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}$

$t = -1.95$

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the highlighters wrote for less than 14 continuous hours.

5 0

2 years ago

In the figure, the radius of the partial circle with center Ais 4 feet.

oee [108]

1)24.50 ;))))))))))

2)45.68 ;)))))))))

7 0

3 years ago

What is the answer to this equation <br> 3/7=c+4/35

sergey [27]

C=11/35

You subtract 4/35 from both sides.

7 0

2 years ago

Read 2 more answers

With one of these is a functionabcd​

With one of these is a functionabcd