7.

The LCM of two numbers is 60. Their GCf is 6 and their difference is 18. What are the two numbers?

Aliun [14]

$LCM(x,y)=60\\
GCF(x,y)=6\\
x-y=18\\\\
LCM(x,y)=\dfrac{|x\cdot y|}{GCD(x,y)}\\
60=\dfrac{|x\cdot y|}{6}\\
|x\cdot y|=360\\\\\\
|x\cdot y|=360\\
x-y=18\\\\
|x\cdot y|=360\\
x=18+y\\\\
|(18+y)\cdot y|=360\\
|18y+y^2|=360\\
18y+y^2=360 \vee 18y+y^2=-360\\
y^2+18y+81=441 \vee y^2+18y+81=-279\\
(y+9)^2=441 \vee (y+9)^2=-279\\
y+9=\sqrt{441} \vee y+9=-\sqrt{441}\\
y=21-9 \vee y=-21-9\\
y=12 \vee y=-30\\\\
x-12=18 \vee x-(-30)=18\\
x=30 \vee x=-12\\\\
\boxed{x=30, y=12 \vee x=-12, y=-30}$

4 0

3 years ago

Read 2 more answers

Which is the pair of congruent right angles?

Alex73 [517]

The little squares at corner-B and corner-E were drawn there
to show that those are right angles.

8 0

3 years ago

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Ms. Johnson is drawing a floor plan of her square room that has an area of 100 ft2. She is using the scale of 0.5 inch =2 ft. Wh

algol [13]

Answer:

it's 2.5 inches cool profile pic to

Step-by-step explanation:

3 0

3 years ago

What percentage of your gross earnings is taken by your employer for FICA?

Leno4ka [110]

Answer:

<em>well non of the answer choices are exact but i would say a/the first one. im not sure but they should add up to about 7.65%.</em>

Step-by-step explanation:

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7 0

2 years ago

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According to a survey, 18% of the car owners said that they get the maintenance service done on their cars according to the sche

Annette [7]

Answer:

a) For this case we define the random variable X="number of car owners in a random sample of 12 who get the maintenance service done on their cars according to the schedule recommended by the auto company". And for this case the distribution for X is:

$X \sim Binom (n =12, p=0.18)$

And the possible values for the random variable are X=0,1,2,3,4,5,6,7,8,9,10,11,12

b) Using the probability mass function we got:

$P(X=3)=(12C3)(0.18)^3 (1-0.18)^{12-3}=0.21506$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

For this case we define the random variable X="number of car owners in a random sample of 12 who get the maintenance service done on their cars according to the schedule recommended by the auto company". And for this case the distribution for X is:

$X \sim Binom (n =12, p=0.18)$

And the possible values for the random variable are X=0,1,2,3,4,5,6,7,8,9,10,11,12

Part b

Find to 3 decimal places the probability that exactly 3 car owners in a random sample of 12 get the maintenance service done on their cars according to the schedule recommended by the auto company.

Using the probability mass function we got:

$P(X=3)=(12C3)(0.18)^3 (1-0.18)^{12-3}=0.21506$

6 0

3 years ago