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Ksivusya [100]
2 years ago
8

(x = 3) y=x+5 How would I solve this problem

Mathematics
1 answer:
Flura [38]2 years ago
5 0
So it would be y=3+5 so you really just add 3+5 and that’s 8 so it would be y=8
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In an arithmetic sequence, if a2= 5 and a10= 19 find a6
OLEGan [10]

Answer:

a₆ = 12

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₂ = 5 and a₁₀ = 19 , then

a₁ + d = 5 → (1)

a₁ + 9d = 19 → (2)

Subtract (1) from (2) term by term to eliminate a₁

8d = 14 ( divide both sides by 8 )

d = 1.75

Substitute d = 1.75 into (1)

a₁ + 1.75 = 5 ( subtract 1.75 from both sides )

a₁ = 3.25

Then

a₆ = 3.25 + 5(1.75) = 3.25 + 8.75 = 12

6 0
3 years ago
What is the result of 5/6 + 2/3
Goryan [66]
You can convert 2/3 into a fraction that makes adding a lot easier.

Since 3 times 2 is equal to 6, you can multiply the numerator and denominator of 2/3 by 2 to get 4/6.

From there, you add 4/6 + 5/6 to get 9/6.

Since both 9 and 6 are divisible by 3, you can simplify the fraction to 3/2.

Your final answer would be 3/2
Which can also be formatted as 1 1/2 or 1.5
4 0
3 years ago
A model village is built to scale. It has a scale of 1 : 23. A road has a real-life length of 1.61 km. What is the length of the
Bess [88]

Answer:

We need to find how much more or less the ratio becomes

1.61 / 23 = 0.07

we multiply 0.07 with 1 to make the ratio even and get your answer

1 x 0.07 = 0.07 on the map

Hope this helps

Step-by-step explanation:

6 0
3 years ago
I need help on this problem. Solve for c
DanielleElmas [232]
First you need to multiply each side by 2

X - C. X - C = d * 2
-------- = d --->
2
Then add X from each side

C = d * 2 + X
8 0
3 years ago
Read 2 more answers
concrete can be made by mixing cement, sand and gravel in the ratio 3:6:8. how much gravel is needed to make 850 cubic meter of
Evgesh-ka [11]

400 cubic meters of gravel is needed to make 850 cubic meters of concrete.

If you wanna know how I got my answer then just ask. :)

Hope this helped!

6 0
3 years ago
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