Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
We want to determine a 80% confidence interval for the mean mercury concentration of water samples
Number of samples. n = 4
Mean or average = 0.470 cc/cubic meter
Standard deviation, s = 0.0581
For a confidence level of 80%, the corresponding z value is 1.28. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
0.470 +/- 1.28 × 0.0581/√4
= 0.470 +/- 1.28 × 0.0566/2
= 0.470 +/- 0.036
The lower end of the confidence interval is 0.470 - 0.036 =0.434
The upper end of the confidence interval is 0.470 + 0.036 =0.506
In conclusion, with a 80% confidence interval, the mean lead mean mercury concentration of the water samples is between 0.434 cc/cubic meter and 0.506 cc/cubic meter
h and k are just arbitrarily choosen names for these functions, and (x) is the variable we do all the calculations with
example: (x) can be some function, while d(x)= 2*f(x) always doubles what f(x) would give you. and in order to talk about the new function we give it a new name.
----------------------
let's have a look into it.
and with a look, I mean a look (screenshot 1)
k(x) basically takes the other equation, doubles its values, but also flips the sign (hence -2*h(x)), and then adds 3 (shifting everything 3 units up)
k(x) is a <em><u>vertical stretch</u></em> [note thatthe zero-pounts stay the same] by a factor of <em><u>-2</u></em>, <em><u>translated up</u></em> [you typed translated right twice, but the +3 in the new equation is safely putting everything 3 units higher].
to be honest, I can't get the meaning of some of the blanks and the options you mentioned don't seem to fit well.
I hope I gave you enough insight to do do the quiz anyways.
pls let me no if you solved it or if you need further explanations.
Answer:
Step-by-step explanation:
The relevant relations here are ...
- the sum of arc measures in a semicircle is 180°
- the sum of angles in a triangle is 180°
<h3>Arc measures</h3>
The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:
arc DA = 180° -CD = 180° -125° = 55°
Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.
∠ABO = 90° -∠AOB = 90° -55°
∠ABO = 35°
<h3>Triangle angles</h3>
In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.
∠ACB = 90° -∠ABC = 90° -55°
∠ACB = 35°
In the figure, angles ABO and ACB have measures of 35°.