<img src="https://tex.z-dn.net/?f=%284x%20-%206y%29" id="TexFormula1" title="(4x - 6y)" alt="(4x

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ra1l [238]

3 years ago

"latex-formula">
hUh I NeDz HeELP

Mathematics

1 answer:

Natalija [7]3 years ago

6 0

Answer:

I’m pretty sure it’s -2xy if it’s not I’m really sorry

Step-by-step explanation:

4-6=-2+xy=-2xy

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Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)

Sedbober [7]

Answer: $\bold{y=-\dfrac{1}{3}x-1}$

Step-by-step explanation:

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\m=\dfrac{-5-1}{2-4} = \dfrac{-6}{-2}=3\quad \rightarrow \quad m_{\perp}=-\dfrac{1}{3}\\$

Next, find the midpoint of (4, 1) and (2, -5):

$Midpoint=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{4+2}{2},\dfrac{1-5}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{6}{2},\dfrac{-4}{2}\bigg)\\\\\\.\qquad \qquad=(3, -2)$

Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

$y - y_1 = m_{\perp}(x - x_1)\\\\y - (-2) = -\dfrac{1}{3}(x - 3)\\\\y + 2=-\dfrac{1}{3}x +1\\\\y =-\dfrac{1}{3}x - 1\\$

6 0

3 years ago

PLEASE I NEED HELP WITH THIS

Ber [7]

Given:

The figure of a circle.

To find:

The measure of arc AD and measure of each arc.

Solution:

The measure of arc is equal to the central angle of that arc.

The central angle of arc AD is 105 degrees. So,

$m(arc(AD))=105^\circ$

The central angle of arc BC is 35 degrees. So,

$m(arc(BC))=35^\circ$

The central angle of arc CD is 50 degrees. So,

$m(arc(CD))=50^\circ$

The central angle of a complete circle is 360 degrees. So,

$m(arc(AD))+m(arc(BC))+m(arc(CD))+m(arc(AB))=360^\circ$

$105^\circ+35^\circ+50^\circ+m(arc(AB))=360^\circ$

$190^\circ+m(arc(AB))=360^\circ$

$m(arc(AB))=360^\circ-190^\circ$

$m(arc(AB))=170^\circ$

Therefore, the measure of arc AD is 105°, the measure of arc BC is 35°, the measure of arc CD is 50° and the measure of arc AB is 170°

3 0

3 years ago

The first term of a geometric series is 3, and the sum of the first term and the second term is 15. What is the sum of the first

Ivan

Sum of n terms in a geometric progression is given by Sn = a1 (1 - r^n) / (1 -r)

3( 1 - 4^6) / (1-4)

= 4,095

5 0

3 years ago

59 and/or 60. Determine if the triangles are similar. If they are similar, find the scale factor from ABC to JKL.

navik [9.2K]

9514 1404 393

Answer:

59) not similar

60)

Step-by-step explanation:

59) The ratios of the side lengths shown cannot be reduced. They are different, so the triangles are not similar.

7:8:12 ≠ 6:7:11

60) The side length ratios both reduce to 8:7:10, so the triangles are similar.

∆ABC ~ ∆JKL

The scale factor is LJ/CA = 25/20 = 5/4. (Multiplying ABC by 5/4 will give JKL.)

8 0

3 years ago

Solve proportion for x 3/2x+5 = 1/9x A. 1/5 B. 1/2 C.5/3 D.16/5

VikaD [51]

I know this but I can't remember how to do the process.

5 0

3 years ago