Answer:
0.5l+0.2s
Step-by-step explanation:
0.10x5<em>l</em> equals 0.5<em>l</em>
0.10x2<em>s</em> equals 0.2<em>s</em>
Answer:
12=12
Step-by-step explanation:
We want to determine the equation in point slope form for the line that is perpendicular to the given line and passing through the point (5.6) .
The equation and the point is;
![y=\frac{2}{3}x+9,(5,6)](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B3%7Dx%2B9%2C%285%2C6%29)
We know that for two lines to be perpendicular, the product of their slopes should be -1.
Therefore, the slope of the perpendicular should be;
![m=-\frac{1}{(\frac{2}{3})}=-\frac{3}{2}](https://tex.z-dn.net/?f=m%3D-%5Cfrac%7B1%7D%7B%28%5Cfrac%7B2%7D%7B3%7D%29%7D%3D-%5Cfrac%7B3%7D%7B2%7D)
The second condition is that the line must pass through the point (5,6) , to do thid, we write the equation of the line in point slope form which is;
![y-y_1=m(x-x_{1_{}})](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_%7B1_%7B%7D%7D%29)
Inserting all values, we have,
![y-6=.-\frac{3}{2}(x-5)](https://tex.z-dn.net/?f=y-6%3D.-%5Cfrac%7B3%7D%7B2%7D%28x-5%29)
That is the final answer.
Answer:
$9398.50
Step-by-step explanation:
Given
![\$1 = 106.40\ ALL](https://tex.z-dn.net/?f=%5C%241%20%3D%20106.40%5C%20ALL)
Required
Equivalent of 1,000,000 ALL
We have:
![\$1 = 106.40\ ALL](https://tex.z-dn.net/?f=%5C%241%20%3D%20106.40%5C%20ALL)
and
![\$x = 1000000\ ALL](https://tex.z-dn.net/?f=%5C%24x%20%3D%201000000%5C%20ALL)
Cross Multiply
![x * 106.40 = 1 * 1000000](https://tex.z-dn.net/?f=x%20%2A%20106.40%20%3D%201%20%2A%201000000)
![106.40x = 1000000](https://tex.z-dn.net/?f=106.40x%20%3D%201000000)
Solve for x
![x = 1000000/106.4](https://tex.z-dn.net/?f=x%20%3D%201000000%2F106.4)
<em></em>
<em> -- Approximated</em>
We need the graphing tool.