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Aleksandr-060686 [28]
3 years ago
12

1.1(1.6x+0.4)-0.44= -17.6

Mathematics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer:

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

x

=

−

10.975

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What is 2 x 9 x 18 x 28 x 46 x 58, its a hard question
Yuliya22 [10]
2x9 is 18x18 is 324 x28 is 9072 x 46 is 417,312 so the x 58 the answer is 24,204,096
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What has no congruent sides and no congruent angles?
Mademuasel [1]
Hey there!

The correct answer to your question is a circle.

A circle doesn't have any congruent sides or congruent angles, meaning they don't have sides or angles that point in the same direction.

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Are these numbers divisible by<br> 2,3,5,10<br> 444:<br> 90:<br> 45:
anyanavicka [17]

444 ÷ 2 = 222

444 ÷ 3 = 148   

90 ÷ 2 =  45   

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 90 ÷ 5 = 18 

90 ÷ 10 = 9

45 ÷  3 = 15   

 45 ÷ 5 = 9

So 444 can be divided into 2 and 3

90 can be divided into  2, 3, 5,  and 10

45 can be divided into  3 and 5

Hope this helps. :) 



6 0
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Evaluate 7C3. 35 210 21 105
nydimaria [60]

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8 0
4 years ago
The number of column inches of classified advertisements appearing on Mondays in a certain daily newspaper is normally distribut
lana66690 [7]

Answer:

The probability there will be between 280 and 360 column inches of classified advertisement

P(280≤X≤360) = P(-2≤Z≤2) = 0.9544

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean  the population = 320

The standard deviation of the Population = 20

Let 'X' be the random variable in a normal distribution

Let 'X' = 280

Z = \frac{x-mean}{S.D} = \frac{280-320}{20} = -2

Let 'X' = 360

Z = \frac{x-mean}{S.D} = \frac{360-320}{20} = 2

<u><em>Step(iii):-</em></u>

The probability there will be between 280 and 360 column inches of classified advertisement

P(280≤X≤360) = P(-2≤Z≤2)

                        = P(z≤2) -P(z≤-2)

                       = P(z≤2)+P(z≤2)

                      = 2P(z≤2)

                     = 2×0.4772     ( from normal table)

                    = 0.9544

6 0
3 years ago
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