Answer:
97.98
Step-by-step explanation:
The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;
Area of the parallelogram = |PQ×PS|
PQ = Q-P and PS = S-P
Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)
PQ = (4,-5,3) - (0,0,0)
PQ = (4,-5,3)
Also, PS = S-P
PS = (8,-12,4)-(0,0,0)
PS = (8,-12,4)
Taking the cross product of both vectors i.e PQ×PS
(4,5,-3)×(8,-12,4)
PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k
PQ×PS = -16i - 40j -88k
|PQ×PS| = √(-16)²+(-40)²+(-88)²
|PQ×PS| = √256+1600+7744
|PQ×PS| = √9600
|PQ×PS| ≈ 97.98
Hence the area of the parallelogram is 97.98
Answer:
AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13
AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13
Step-by-step explanation:
Because it is a equilateral triangle, it means all sides have the same length.
AB = AC
5/4 y - 1 = 7/3 y - 2
5/4 y - 7/3 y = -2 +1
-13/12 y = -1
y = 12/13
input y to the equation.
AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13
AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13
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Slope intercept form: y = 3/4 x - 7
Point slope form: y + 7 = 3/4 (x+0)
Answer:
824.65
Step-by-step explanation:
Okay Let's say
2x + 3 = 45
-3 -3
----------------
2x = 42
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2 2 x = 21