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BARSIC [14]
4 years ago
13

What is the value of x3 . y4 when x 3 and y = 0?

Mathematics
2 answers:
jonny [76]4 years ago
6 0

Answer:

<h2>0</h2>

Step-by-step explanation:

x^3 \times y^4\\\\x = 3\\y =0 \\\\(3)^3\times 0^4\\\\3^3\times\:0^4\\\\\mathrm{Apply\:rule}\:0^a=0\\0^4=0\\\\=3^3\times\:0\\\\\mathrm{Apply\:rule}\:0\times\:a=0\\=0

jasenka [17]4 years ago
6 0

Answer:

We need to calculate x^3*y^4 for x = 3 and y = 0.

First thing we do is replacing x and y on x^3*y^4:

3^3*0^4

Now, we only need to solve it:

3^3*0^4 = 27 * 0 = 0

Remember that 3^3 = 3*3*3

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Identify the decimal equlivant that does not have the same characteristic as the other three.
Paul [167]

Answer:

3/12 and 2/12 cannot

Step-by-step explanation:

4 0
3 years ago
I used Cauchy-Schwarz inequality but it took too much time to finish. Is there any way faster?​
ExtremeBDS [4]

Answer:

x = 1, x = -1

Step-by-step explanation:

Given 4(2^{2x}+2^{-2x})-4(2^x+2^{-x})-7=0

Use substitution

t=2^x+2^{-x}

Square previous equality:

t^2=(2^x+2^{-x})^2\\ \\t^2=(2^{x})^2+2\cdot 2^x\cdot 2^{-x}+(2^{-x})^2\\ \\t^2=2^{2x}+2\cdot 2^{x-x}+2^{-2x}\\ \\t^2=2^{2x}+2\cdot 2^0+2^{-2x}\\ \\t^2=2^{2x}+2\cdot 1+2^{-2x}\\ \\t^2=2^{2x}+2+2^{-2x}\\ \\2^{2x}+2^{-2x}=t^2-2

Substitute it into the equation:

4(t^2-2)-4t-7=0\\ \\4t^2-8-4t-7=0\\ \\4t^2-4t-15=0

Solve this quadratic equation:

D=(-4)^2-4\cdot 4\cdot (-15)=16+16\cdot 15=16(1+15)=16\cdot 16\\ \\\sqrt{D}=16\\ \\t_{1,2}=\dfrac{-(-4)\pm 16}{2\cdot 4}=\dfrac{4\pm 16}{8}=\dfrac{5}{2},\ -\dfrac{3}{2}

Note that

2^x>0\\ \\2^{-x}>0,

then

t=2^x+2^{-x}>0,

so

2^x+2^{-x}=\dfrac{5}{2}

Solve this equation using substitution

2^x=u\\ \\2^{-x}=\dfrac{1}{2^x}=\dfrac{1}{u}

Thus,

u+\dfrac{1}{u}=\dfrac{5}{2}\\ \\2u^2+2=5u\ \ [\text{Multiplied by 2u}]\\ \\2u^2-5u+2=0\\ \\D=(-5)^2-4\cdot 2\cdot 2=25-16=9\\ \\\sqrt{D}=3\\ \\u_{1,2}=\dfrac{-(-5)\pm 3}{2\cdot 2}=\dfrac{5\pm 3}{4}=2,\ \dfrac{1}{2}

Now,

u=2\Rightarrow 2^x=2,\ x=1\\ \\2^x=\dfrac{1}{2}\Rightarrow 2^x=\dfrac{1}{2}=2^{-1},\ x=-1

7 0
3 years ago
The line passes through the points (-5,0) and (-1,-4)<br> The slope of the line is
kotykmax [81]

Answer:

-1.

Step-by-step explanation:

First, you find the distance from the first x coordinate to the second. This is done by doing -5 - -1 (aka -5 + 1), which equals -4. Then, you find the distance form the first y coordinate to the second. THis is done by doing 0 - -4 (aka 0 + 4), which equals 4. Then, you divide the distance of the y's over the distance of the x's, which gets you the slope, which is -1. Hope this helped!

8 0
3 years ago
X+4=7 one step equations
nexus9112 [7]
This one is pretty easy. 

x+ 4 = 7
Subtract 4 from both sides so you can isolate the x (Get the x alone) 
x = 7 -4
x = 3
That's your answer. 3. 
3 0
3 years ago
Read 2 more answers
What is equivalent to -23-(26)=x
ANTONII [103]
I’m not sure if this is what your looking for but x = -49
4 0
3 years ago
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