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2 years ago

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The two triangles at right are congruent. What is the perimeter of each? A 4 ft 5 ft 5 ft 6 ft

1 answer:

dlinn [17]2 years ago

7 0

Hey yaal its 36446473

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Could someone help me arrange these pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (2

Zina [86]

Answer:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

Step-by-step explanation:

Required

Arrange in increasing order of slope

Slope (m) is calculated using:

$m = \frac{y_2 -y_1}{x_2 - x_1}$

So, we have:

(a) (15, 30) and (20, 40)

$m = \frac{40 -30}{20- 15}$

$m = \frac{10}{5}$

$m =2.00$

(b) (12, 32) and (18, 48)

$m = \frac{48 -32}{18- 12}$

$m = \frac{16}{6}$

$m = 2.67$

(c) (27, 12) and (72, 32)

$m = \frac{32-12}{72- 27}$

$m = \frac{20}{45}$

$m = 0.44$

(d) (45, 15) and (60, 20)

$m = \frac{20-15}{60- 45}$

$m = \frac{5}{15}$

$m = 0.33$

(e) (27, 2) and (243, 18)

$m = \frac{18-2}{243- 27}$

$m = \frac{16}{216}$

$m = 0.07$

(f) (18, 63) and (24, 84)

$m = \frac{84-63}{24- 18}$

$m = \frac{21}{6}$

$m = 3.50$

(g) (63, 9) and (84, 12)

$m = \frac{12 -9}{84- 63}$

$m = \frac{3}{21}$

$m = 0.14$

From least to greatest slope, the pair of points are:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

6 0

2 years ago

Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r

PolarNik [594]

Answer:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

$(a-b)^2=a^2-2ab+b^2$

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}$

$\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8$

$\displaystyle b=\frac{1}{7}mpz^4$

Nos cercioramos de que el término central es 2ab:

$\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4$

Operando:

$\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5$

Una vez verificado, ahora podemos decir que:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

5 0

2 years ago

A truck drove at an average rate of 45 miles per hour on the highway and 20 miles per hour once it entered the city. If it took

SIZIF [17.4K]

45 * 1.6 + 20 * 1.4 = 100
72 + 28 = 100
100 = 100

7 0

3 years ago

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Jenna measured a paper clip at 2 7/16 inches long. What would be the length of 6 paper clips placed end to end

MariettaO [177]

The answer is 14.625 inches

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2 years ago

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I struggle a lot with pre-algebra pls help

ch4aika [34]

Answer:

Polygon B is similar to Polygon A.

Step-by-step explanation:

Polygon B has a <em>scale factor</em> of 2, because Polygon B looks identical to A, except the measurements are twice as large.

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2 years ago