We are to solve the total area of the pyramid and this can be done through area addition. We first determine the area of the base using the Heron's formula.
A = √(s)(s - a)(s - b)(s - c)
where s is the semi-perimeter
s = (a + b + c) / 2
Substituting for the base,
s = (12 + 12 + 12)/ 2 = 18
A = (√(18)(18 - 12)(18 - 12)(18 - 12) = 62.35
Then, we note that the faces are just the same, so one of these will have an area of,
s = (10 + 10 + 12) / 2 = 16
A = √(16)(16 - 12)(16 - 10)(16 - 10) = 48
Multiplying this by 3 (because there are 3 faces with these dimensions, we get 144. Finally, adding the area of the base,
total area = 144 + 62.35 = 206.35
Answer:
i am not sure thi sis the first one
Answer:
irrational number, nonrepeating decimal
Step-by-step explanation:
Answer:
7i.
Step-by-step explanation:
Note : The given expression must be 
.
We have to write this radical value in the imaginary value.
The given value can be rewritten as
![[\because \sqrt{ab}=\sqrt{a}\sqrt{b}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%7Bab%7D%3D%5Csqrt%7Ba%7D%5Csqrt%7Bb%7D%5D)
![[\because \sqrt{-1}=i]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%7B-1%7D%3Di%5D)
Therefore, the required expression is 7i.
Answer:
y = 100°
Step-by-step explanation:
x = 40° (vertical angles are congruent)
y is an exterior angel of a triangle that has two opposite internal angles, x (40°) and 60°.
According to the exterior angle of a triangle, thus:
y = 40 + 60
y = 100°
