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sergey [27]
1 year ago
14

Circle P is centered at the origin. Which of the following statements can be used to

Mathematics
1 answer:
a_sh-v [17]1 year ago
3 0

the correct option is:

<em>"The distance from the origin to point A is equal to the radius of circle P. Therefore, point A lies on circle P."</em>

<em />

<h3>Which of the following statements can be used to construct an algebraic proof the point A lies on circle P?</h3>

A circle is defined as the set of equidistant points to a given point which is the center of the circle.

That distance to the center is called the radius.

Here, the center is at the point (0, 0), also called the origin, so if the distance between the point A and the origin, then point A lies on top of the circle P.

From that, we conclude that the correct option is:

<em>"The distance from the origin to point A is equal to the radius of circle P. Therefore, point A lies on circle P."</em>

<em />

That is the only proof that we can (and should) use to prove that a point lies on a circle.

<em />

If you want to learn more about circles:

<em>brainly.com/question/1559324</em>

<em>#SPJ1</em>

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The functions f (x) = 1/2x-3 and g(x) = -2x+ 2 intersect<br> at x = -2. True or false?
Norma-Jean [14]

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Answer:

  False

Step-by-step explanation:

f(-2) = (1/2)(-2) -3 = -1 -3 = -4

g(-2) = -2(-2) +2 = 4 +2 = 6

The function values are not the same at x=-2, so the graphs do not intersect there.

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The graphs intersect at x=2.

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3 years ago
15. Solve for the variable. Show all work.
MrRissso [65]
Add 15 and 9, then subtract that by 87. 63 should be your answer.
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3 years ago
Factorise:x^2-y^2-x-y​
ivanzaharov [21]

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Answer:

  (x -y -1)(x +y)

Step-by-step explanation:

The expression can be factored by grouping.

  x^2 -y^2 -x -y = (x^2 -y^2) -(x +y)

  = (x -y)(x +y) -1(x +y)

  = (x -y -1)(x +y)

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It is useful to know that a difference of squares is factored as ...

  a^2 -b^2 = (a -b)(a +b)

7 0
3 years ago
Which expressions are equivalent to the given expression?
Komok [63]

-51 - 6i AND -3 + 2i - 2(24) - 8i are correct :)

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2 years ago
A = {multiples of 2}, B = {multiples of 3), C = {multiples of 7}.
ss7ja [257]

Let's check the sets

  • A={2,4,6,8,..}
  • B={3,6,9..}
  • C={7,14,21..}

Find LCM

  • 2×3×7=42

  • (AnBnC)={42}

Recreate the sets

  • A={2,4,6,8,10,12..,42}
  • B={3,6,9,..,42}
  • C={7,14..42}

Now

  • n(A)=21
  • n(B)=14
  • n(C)=6

Hence

Universal Set =U

\\ \sf\longmapsto U\in R^{+}-\{2,3,4,6,7,8,9,12,14,15,16,18,20,21,22,24,25,26,27,28,30,32,33,34,35,36,38,39,40 ,42\}

6 0
2 years ago
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