Those two functions just miss each other so there are no real solutions. Every polynomial with complex coefficients has complex solutions.









Answer:
The answer is 4th point
Step-by-step explanation:
c∝b
c = k(b)
Let c = 3
b = 1
3 = k(1)
k = 3
c = 3b
Try:
Let c = 12
12 = 3b
b = 4 (proven)
Answer:
M=11
Step-by-step explanation:
Answer:
The question doesn't make sense.
Step-by-step explanation:
True, because like any other factual statements or seem to be factual, only one counterexample is needed to make it false.