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Artemon [7]
3 years ago
7

Join the zoommmmmmmmmm

Mathematics
2 answers:
Masteriza [31]3 years ago
8 0
I will! One second lol
seropon [69]3 years ago
4 0

Answer:

UHMMMMMMM

Step-by-step explanation:

that's just pls time to run

You might be interested in
Which ordered pair is a solution to the equation y = 6x - 4?
Yuri [45]

Answer:

Here are 3 different pairs (0,4) , (1,2) , (2,8)

Step-by-step explanation:

Hope this helped

7 0
3 years ago
The produce manager at a market orders 10 lb of​ tomatoes, 20 lb of​ zucchini, and 40 lb of onions from a local farmer one week.
rewona [7]

Answer:

(A) A=\left[\begin{array}{ccc}10&20&40\end{array}\right]

(B) B=\left[\begin{array}{ccc}11&22&44\end{array}\right]

(C) A+B=\left[\begin{array}{ccc}21&42&84\end{array}\right]

Step-by-step explanation:

The manager ordered 10 lb of​ tomatoes, 20 lb of​ zucchini, and 40 lb of onions from a local farmer one week.

(A)

Matrix <em>A</em> represents the amount of each item ordered. ​It is 1 × 3 matrix.

Then matrix <em>A</em> is:

A=\left[\begin{array}{ccc}10&20&40\end{array}\right]

(B)

Next week the manager increases the order of all the products by 10%.

Then the amount of new orders are:

Tomatoes =10\times [1+\frac{10}{100}]=10\times1.10=11

Zucchini =20\times [1+\frac{10}{100}]=20\times1.10=22

Onions =40\times [1+\frac{10}{100}]=40\times1.10=44

Th matrix <em>B</em> represents the amount of each order for the next week. Then matrix <em>B</em> is:

B=\left[\begin{array}{ccc}11&22&44\end{array}\right]

(C)

Add the two matrix <em>A</em> and <em>B</em> as follows:

A+B=\left[\begin{array}{ccc}10&20&40\end{array}\right]+\left[\begin{array}{ccc}11&22&44\end{array}\right]\\=\left[\begin{array}{ccc}(10+11)&(20+22)&(40+44)\end{array}\right]\\=\left[\begin{array}{ccc}21&42&84\end{array}\right]

The entries of the matrix (<em>A</em> + <em>B</em>) represent the amount of tomatoes, zucchini and onions ordered for two weeks.

5 0
3 years ago
a sample of 546 boys aged 6–11 was weighed, and it was determined that 89 of them were overweight. A sample of 508 girls aged 6–
AleksAgata [21]

Answer:

p-value:  0.6527

Step-by-step explanation:

Hello!

You have two samples to study, from each sample the weight of each child was measured and counted the total of overweight kids (x: "success") in each group:

Sample 1 (Boys aged 6-11)

n₁= 546

x₁= 89

^p₁= x₁/n₁ = 89/546 ≅0.16

Sample 2 (girls aged 6-11)

n=508

x= 74

^p= x/n = 74/508 ≅ 0.15

If the hypothesis statement is "The proportion of boys that are overweight differs from the proportion of girls that are overweight", the test hypothesis is:

H₀: ρ₁ = ρ₂

H₁: ρ₁ ≠ ρ₂

This type of hypothesis leads to a two-tailed rejection region, then the p-value will also be two-tailed. To calculate the p-value you have to first calculate the value of the statistic under the null hypothesis, in this case, is a test for the difference between two proportions:

Z=<u>      (^ρ₁ - ^ρ₂) - (ρ₁ - ρ₂)        </u> ≈ N(0;1)

    √(ρ` * (1 - ρ`) * (1/n₁ + 1/n₂))

ρ`=<u> x₁ + x₂  </u> = <u>  89+74     </u> = 0.154 ≅ 0.15

     n₁ + n₂     546 + 508

Z⁰ᵇ =<u>          (0.16-0.15) - (0)                    </u>

       √(0.15 * (1 - 0.15) * (1/546 + 1/508))

Z⁰ᵇ = 0.45

I've mentioned before that in this test you have a two-tailed p-value. The value calculated (0.45) corresponds to the right or positive tail and the left tail is symmetrical to it concerning the distribution mean, in this case, is 0, so it is -0.45. To obtain the p-value you need to calculate the probability of both values and add them:

P(Z>0.45) + P(Z<-0.45) = (1- P(Z<0.45)) + P(Z<-0.45) = (1-0.67364) + 0.32636 = 0.65272 ≅ 0.6527

p-value:  0.6527

Since there is no signification level in the problem, I'll use the most common to reach a decision. α: 0.05

Since the p-value is greater than α, you do not reject the null Hypothesis, in other words, there is no significative difference between the proportion of overweight boys and the proportion of overweight girls.

I hope it helps!

3 0
3 years ago
How much is House A worth after two years? Round your answer to the nearest dollar.
Gekata [30.6K]

Answer:

see below

Step-by-step explanation:

Take the original value times the appreciation and add the original value

Do this for each year

House A

year 1:

 new value = 125260+ 125260* .05

                    =125260 +6263

                     =131523

year 2:

 new value = 131523+131523* .05

                    131523+6576.15

                         138099.15

Nearest dollar  138099

House B

year 1:

 new value = 120160+ 120160* .06

                    =120160 +7209.60

                     =127369.6

year 2:

 new value = 127369.60+127369.6* .05

                    127369.60+7642.18

                         135011.78

Nearest dollar  135012

4 0
3 years ago
Read 2 more answers
How do I do this? I don't get it can you help me please
masya89 [10]
The base is 6 so you'll need to replace b with 6 and the height is 8 so you'll need to replace h with 8.
4 0
3 years ago
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