2 years ago

Join the zoommmmmmmmmm

2 answers:

8 0

I will! One second lol

4 0

Answer:

UHMMMMMMM

Step-by-step explanation:

that's just pls time to run

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KATRIN_1 [288]

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Neko [114]

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devlian [24]

Hello,
$f(1)=2\\
f(2)= \dfrac{2}{5} =2*5^{-1}\\
f(3)= \dfrac{2}{25} =2*5^{-2}\\
f(4)= \dfrac{2}{125} =2*5^{-3}\\\\

\boxed{f(x)= 2*5^{-x}} \\


$

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3 years ago

Ksivusya [100]

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2 years ago