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Dafna1 [17]
2 years ago
14

Hiiii everyone my previous account has been deleted who knows me plz follow​​​

Mathematics
1 answer:
Dahasolnce [82]2 years ago
3 0

Answer:

I don't know you but I can follow you if you want

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Use the expression 5.2v - (30 ÷ 6) + 12 to answer 9-10.
m_a_m_a [10]
30 ÷ 6 represents a quotient.
30 is the dividend. 6 is the divisor. The quotient is 5.
:::::
5.2v represents a product of two factors.
5.2 and v are both factors.
5.2 is the multiplicand and v is the multiplier.
8 0
2 years ago
The chi-square test statistic is χ2 = 18.68 and the P-value is between 0.0025 and 0.005. What conclusion should the researcher m
diamong [38]

We don't know what the exact p-value is, but we are told that it's as large as 0.005 which is smaller than alpha = 0.05

Since the p-value is smaller than alpha, this means we <u>reject the null hypothesis</u>.

The way you can remember this is "if the p-value is low, then the null must go". By "low", I mean "smaller than alpha".

Recall that the p-value is the probability of observing that specific test statistic, or larger. So the chances of chi-squared being 18.68 or larger is a probability between 0.0025 and 0.005; there's a very small chance of this happening. The p-value is based entirely on the assumption that the null is correct. But if the null is correct, then the chances of landing on this are very small. We have a contradiction that basically leads to us concluding the null must not be the case. It's not 100% guaranteed of course, but it's fairly strong evidence.

In short, the p-value being smaller than alpha = 0.05 means we reject the null.

In order to accept the null, the p-value must be 0.05 or larger.

5 0
3 years ago
One morning, the temperature was -5 ferenhight. By noon, the temperature had increased 12 degrees. What was the temperature at n
Papessa [141]

Answer:

Noon\ Temperature = 7F

Step-by-step explanation:

Given

Initial Temperature = -5F

Change (by noon) = 12 degrees

Required

Determine the temperature at noon

The temperature by noon is calculated as thus;

Noon\ Temperature = Initial\ Temperature + Change

Substitute values for Initial temperature and change

Noon\ Temperature = -5F + 12

Noon\ Temperature = 7F

Hence, the temperature at noon is 7F

6 0
3 years ago
What happens to the value of the expression 150 - j as j decreases?
Step2247 [10]

Answer:

it increases

Step-by-step explanation:

honestly... i just guessed but its right

7 0
3 years ago
Read 2 more answers
If a=4 and b= -6, work out 5a-2b
Lelu [443]

Answer:

32

Step-by-step explanation:

5(4)-2(-6) = 20 plus 12 = 32

7 0
2 years ago
Read 2 more answers
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