Using the normal distribution, it is found that 1851 people would have an IQ less than 115.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:


Z = 1
Z = 1 has a p-value of 0.8413.
Out of 2200 people:
0.8413 x 2200 = 1851.
More can be learned about the normal distribution at brainly.com/question/27643290
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Answer:
u=92
Step-by-step explanation:
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C. The distance around the circle is the correct answer.
If u = ln(x^(1/3))
then by the chain rule
du = [1/x^(1/3)] * (1/3)x^(-2/3) dx = (1/3)(1/x) dx.
You could get there faster by noting that
ln(x^(1/3)) = (1/3) ln(x), so du = (1/3) dx/x