Answer:
Check attachment for orderliness of question
Step-by-step explanation:
We want to the equation in an exact form
M(x, y) dx + N(x, y) dy = 0.
xy² dy/dx = y³− x³
Cross multiply
Then,
xy²dy=(y³-x³)dx
xy²dy - (y³-x³)dx = 0
xy²dy + (x³-y³)dx=0
Therefore,
(x³-y³)dx + xy²dy=0
Can only be an exact equation if and only if
dM/dy=dN/dx
From the equation
M=(x³-y³)
Then, dM/dy=-3y²
Also, N=xy²
dN/dx=y²
Since dM/dy ≠ dN/dx
Then it is not an examct equation and we can say
M≠(x³-y³)
And
N≠(xy²)
Answer:
As far as i know you should go for LCM that would be more convenient and easy to do
True. These answers show a relationship because you add eight every time the pack goes higher.
Answer:
3.50
Step-by-step explanation:
doesnt change therefore its constant
brainliest answer please
