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3 years ago

Pls help i will mark brainliest!:) thank you!;D

Mathematics

1 answer:

pashok25 [27]3 years ago

7 0

<h2>ANSWER</h2>

Here the two points given on the graph A and B

To find : The distance in between the two points we know distance in between two point on a graph 

= 

 $\sqrt{ {(x2 - x1)}^{2} } + \sqrt{ {(y2 - y1)}^{2} }$ 

The Point A = (0,0)

The point B = (3,6)

so the distance in between points A and B 

 $\sqrt{ {(0 - 0)}^{2} } + \sqrt{ {(6 - 3)}^{2} }$ 

 $\sqrt{ {3}^{2} }$ 

 $3$ 

So 3.0 is the distance

Hope it helps

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To start off, the wording of this question is pretty technical. Let's reword the question to make it a bit easier to understand.

From the open interval from -2 to 5 (meaning between but not including those integers), list every integer for x at which x approaches a defined y point on the curve, regardless of whether it actually takes that y value at that point.

Let's start with the first eligible integer, -1.
The limit, from both sides, as x approaches -1 is y=-1.
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At 0, x continuous and defined on the curve where you would expect it, and therefore the limit at x=0 is its y value at that point, 0.

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x=2 has a clear defined limit. It is continuous and defined at that point. The limit looks to be around y= 1.8

x=3 does not feature a clearly defined, finite value, since the limit at x=3 is
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Answers are x=-1, x=0, x=2, and x=4
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