Please help me!!! i’m terrible at math. i’ll mark you brainlist

JulsSmile [24]

Answer:

Step-by-step explanation:

Given (x - 2)^2 + (y + 3)^2 = 9, compare this to the standard equation of a circle, (x - h)^2 + (y - k)^2 = r^2.

It then becomes obvious that h = 2 and k = -3; the coordinates of the center of the circle are (2, -3).

If r^2 = 9, then r must be 3. This is the radius of the circle.

To draw this circle: Plot the center (2, -3). Take a compass and open it up so that the distance between the compass points is 3, representing the radius of the circle. Now use the compass to draw a circle with radius 3 and center at (2, -3).

3 0

3 years ago

How would I solve this and where would I put the dots?

Maslowich

Step-by-step explanation:

You would solve it by turning it into a equation and solving it. You would place the dots on the graph and put them in the points where they are supposed to go.

8 0

3 years ago

A boat travels 26 miles East from a lighthouse then changes direction traveling 15(deg) South of West for 13 miles. How far is t

elixir [45]

Answer:

The ship is 25.54 miles far from the light house.

Step-by-step explanation:

It is given that A boat travels 26 miles East from a lighthouse then changes direction traveling 15° South of West for 13 miles that is :

BC=c, BA=26 miles and CA=13miles

Then, applying the cosine formula in ΔABC, we get

$(BC)^2=(BA)^2+(AC)^2-2(BA)(AC)cos15^{\circ}$

⇒ $c^2=(26)^2+(13)^2-2(26)(13)(0.965)$

⇒ $c^2=676+169-675(0.965)$

⇒ $c^2=652.34$

⇒ $c=25.54miles$

Therefore, the ship is 25.54 miles far from the light house.

6 0

4 years ago

An insurance company estimates 45 percent of its claims have errors. The insurance company wants to estimate with 99 percent con

nydimaria [60]

Answer:

We need a sample size of at least 657.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

45 percent of its claims have errors.

So $\pi = 0.45$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

What sample size is needed if they wish to be within 5 percent of the actual

This is a sample size of at least n, in which n is found when M = 0.05.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.05 = 2.575\sqrt{\frac{0.45*0.55}{n}}$

$0.05\sqrt{n} = 1.28$

$\sqrt{n} = \frac{1.28}{0.05}$

$\sqrt{n} = 25.62$

$\sqrt{n}^{2} = (25.62)^{2}$

$n = 656.4$

We need a sample size of at least 657.

6 0

3 years ago

A student received a coupon for 17% off the total purchase price at a clothing store. Let c be the

lys-0071 [83]

C - 0.17c = 0.83c
When you write “c” at the start, or x or whatever, it has an understood (invisible) number 1. So you’re subtracting the decimal on the next variable from 1.

7 0

3 years ago