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2 years ago

10

Please help me!!! i’m terrible at math. i’ll mark you brainlist

1 answer:

Zepler [3.9K]2 years ago

3 0

Get p h o t o m a t h

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Is 6-6 and 1-6 equal

uranmaximum [27]

Answer:

no

Step-by-step explanation:

6-6=0

1-6=-5

7 0

3 years ago

46 Two light houses ash their lights every 30 seconds and 40 seconds respectively. Given that they last ashed together at 10:40

IRISSAK [1]

30,60,90,120
40,80,120

they will both " ash " in 120 seconds (thats 2 minutes)...so they will both ash at
10:42 a.m.

8 0

3 years ago

Name this figure.

vitfil [10]

Answer:

The figure is a Rhombus.

Step-by-step explanation:

Cause well it looks like a Diamond pretty much. Hope this helps.

3 0

2 years ago

Read 2 more answers

Help help help math math

Salsk061 [2.6K]

Answer:

V = 4000 ft³

Step-by-step explanation:

if diameter is 20 then radius is half that, or 10

use formula:

V = 4/3(3)(10)³

V = 4(10)³

V = 4(1000)

V = 4000 ft³

7 0

2 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

as

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago