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Jlenok [28]
3 years ago
6

PLSSSS HELPPPP ASAPPP

Mathematics
1 answer:
Feliz [49]3 years ago
7 0

Answer:

3x+18+93=180

3x+111-111 =180-111

3x. =69

X=23

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If log2 5 = a, log2 3 = b and log2 7 = c, determine an expression for log2 (25/21) in terms of a, b, and c
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Answer:

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log_{2} 5 = a\\log_{2} 3 = b\\log_2 7 = c\\

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log_2 \frac{25}{21}.

We can form the numerator using just the first fact (since 5^2 is 25) and the denominator using the latter two (since 3*7 = 21).

log_2 \frac{25}{21} = log_2 \frac{5^2}{3*7}.

The logarithm of a division can be expanded by subtracting the numerator and denominator (while still keeping the log). The logarithm of a product can be expanded by adding the terms while keeping the log. If the logarithm is raised to a power, we can bring it down as a factor:

log_2 \frac{5^2}{3*7} = log_2(5)^2 - log_2 (3*7) = 2 log_2(5) - (log_2 3 + log_2 7)

= 2 log_2(5) - log_2 3 - log_2 7 .

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