
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
The answers would be 1, 2, 4, 5, 8, 10, 20, and 40.
- 38z, because -10z - 28z = 38, but you have to change into addition and that will be equal -38z.
<u>Answer:</u>
<h2>d ≈ 7.07</h2>
<u>Steps:</u>
d = √( (3-(-2))² + (-1-4)² )
d = √( (3+2)² + (-1-4)² )
d = √( 5² + (-5)² )
d = √( 25 + 25 )
d = √50
<h2>d ≈ 7.07</h2>