A juggler throws a beanbag into the air with a speed of 1.0 \dfrac{\text m}{\text s} 1.0 s m 1, point, 0, start fraction, star
t text, m, end text, divided by, start text, s, end text, end fraction . How long does it take for the beanbag to reach its maximum height?
1 answer:
Answer:
0.102 s
Step-by-step explanation:
Given the following :
Initial speed (u) = 1 m/s
How long does it take the bean bag to reach maximum height?
At maximum height, the final velocity v = 0
Acceleration due to gravity g = - ve (upward motion) =? - 9. 8m/s²
Using the relation:
v = u + gt
0 = 1 - 9.8t
9.8t = 1
t = 1 / 9.8
t = 0.102 s
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