Question

A juggler throws a beanbag into the air with a speed of 1.0 \dfrac{\text m}{\text s} 1.0 s m ​ 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction . How long does it take for the beanbag to reach its maximum height?

Answer 1

Answer:

0.102 s

Step-by-step explanation:

Given the following :

Initial speed (u) = 1 m/s

How long does it take the bean bag to reach maximum height?

At maximum height, the final velocity v = 0

Acceleration due to gravity g = - ve (upward motion) =? - 9. 8m/s²

Using the relation:

v = u + gt

0 = 1 - 9.8t

9.8t = 1

t = 1 / 9.8

t = 0.102 s